我正在使用Oracle 10.2.0.1
我有一个表“AppUser”,其中包含列(id,username,pass,count)
我想做的是:check username
if (username exists )
{
check password
if (password exists)
{
set count = 0 and return 1
}
else (password not exists)
{
check count < = 5
if true(count + 1 and return 0)
else return 2 (user locked)
}
}
我已将序列“countid”设为最小值= 1,最大值= 5,inc为1,循环为真。
现在我想制作一个包并从后面的代码中调用它。
到目前为止我有这个..但它给了我错误ORA-00900:无效的SQL语句
IF count(select "LoginName" from "ApplicationUser" where exists (select "Count" from
"ApplicationUser" where Count<=5) and "LoginName" =:param1) >0
THEN select "Pass" from "ApplicationUser" where "Pass"=:param2;
ELSE return 0;
END IF;
答案 0 :(得分:1)
你尝试做的是相当复杂的陈述,这很难制作,很难维护和修改。尝试完全按照你在&#34;中所写的那样分解你的问题。我想做的是&#34;部分。 PL / SQL使您可以编写一个很好的分解代码。
begin
select username into v_user_name where ...;
if (username is not null) then
select password into v_password from ...;
if (v_password is not null) then
update AppUser set count = 0 where ...;
return 1;
else
select count into v_count from ...;
if v_count<5 then
update AppUser set count=count+1 where....;
return 0;
else
return 2;
end if;
end if;
end if;
end;
答案 1 :(得分:0)
update usertable
set count = 0
where id = @id
declare @i int, @Getpassword nvarchar(50),@GetCount int
set @i = 0 ;
while(@i <= 5)
begin
select @Getcount = count from usertable where id = @id
if(@GetCount > 5 or @getCount = 5)
begin
-- block user here
print 'user blocked'
set @i = 6
end
else
begin
print 'checking'
select @Getpassword = password from usertable where id = @id
if(@Getpassword = @password)
begin
print 'validated'
set @i = 6
end
else
begin
print 'not validated'
set @i = @i + 1;
print 'Current Count '
print @getcount
print 'updating count'
update usertable
set count = @getcount +1
where id = @id
end
end
end
RETURN