Question

我想问一下如何计算包含单词的变量数量。

例如，我有3个变量：

$var1 = "Alpha Beta Cupcake Doughnut";
$var2 = "Cupcake Doughnut Eclair Froyo";
$var3 = "Gingerbread Doughnut";

我希望结果是这样的（“The word”：“How times” - “variable（s）”）：

Alpha : 1 - $var1(only 1 variable contain word Alpha)
Beta : 1 - $var1
Cupcake : 2 - $var1 and $var2 (2 variables contain word Cupcake)
Doughnut : 3 - $var1, $var2, and $var3(3 variables contain word doughnut)
Eclair : 1 - $var2
Froyo : 1 - $var2
Gingerbread : 1 - $var3

有谁知道怎么做？如果有这个解决方案的示例代码，我真的很感激

Answer 1

您将变量放入数组

   $variables = array();
    $variables[] = $var1;
    $variables[] = $var2;
    $variables[] = $var3;

您为每个单词创建一个包含计数的数组

$words = array();

你数字

foreach($variables as $variable)
{
  $wordsInVariable = explode(' ',$variable);
  foreach($wordsInVariable as $word)
  {
    if(isset($words[$word])
    {
       $words[$word] += 1;
    }else
    {
       $words[$word] = 1;
    }
  }
}

打印结果

print_r($words) // or whatever

Answer 2

将您的变量字符串分解为数组，然后只计算条目。我认为最简单的方法是：

$arrayWithVariables = array_count_values(array_merge(
        explode(' ', $var1), 
        explode(' ', $var2), 
        explode(' ', $var3)
    ));

结果数组是：

array
  'Alpha' => int 1
  'Beta' => int 1
  'Cupcake' => int 2
  'Doughnut' => int 3
  'Eclair' => int 1
  'Froyo' => int 1
  'Gingerbread' => int 1

计算计数单词的多少变量（PHP）

2 个答案: