从字符串反序列化而不是TextReader

时间:2010-02-27 14:29:33

标签: c# xml serialization

我想改变我的代码:

string path = @"c:\Directory\test.xml";
XmlSerializer s = new XmlSerializer(typeof(Car));

TextReader r = new StreamReader(path);

Car car = (Car)s.Deserialize(r);
r.Close();

代码将XML转换为字符串,然后将字符串转换为对象Car。

这可能吗?

5 个答案:

答案 0 :(得分:233)

public static string XmlSerializeToString(this object objectInstance)
{
    var serializer = new XmlSerializer(objectInstance.GetType());
    var sb = new StringBuilder();

    using (TextWriter writer = new StringWriter(sb))
    {
        serializer.Serialize(writer, objectInstance);
    }

    return sb.ToString();
}

public static T XmlDeserializeFromString<T>(this string objectData)
{
    return (T)XmlDeserializeFromString(objectData, typeof(T));
}

public static object XmlDeserializeFromString(this string objectData, Type type)
{
    var serializer = new XmlSerializer(type);
    object result;

    using (TextReader reader = new StringReader(objectData))
    {
        result = serializer.Deserialize(reader);
    }

    return result;
}

使用它:

//Make XML
var settings = new ObjectCustomerSettings();
var xmlString = settings.XmlSerializeToString();

//Make Object
var settings = xmlString.XmlDeserializeFromString<ObjectCustomerSettings>(); 

答案 1 :(得分:76)

如果您将XML存储在字符串变量中,则可以使用StringReader

var xml = @"<car/>";
var serializer = new XmlSerializer(typeof(Car));
using (var reader = new StringReader(xml))
{
    var car = (Car)serializer.Deserialize(reader);
}

答案 2 :(得分:14)

1-liner,将XML字符串textYourType作为预期的对象类型。与其他答案差别不大,只是压缩到1行:

var result =  (YourType)new XmlSerializer(typeof(YourType)).Deserialize(new StringReader(text));

答案 3 :(得分:6)

static T DeserializeXml<T>(string sourceXML) where T : class
{
    var serializer = new XmlSerializer(typeof(T));
    T result = null;

    using (TextReader reader = new StringReader(sourceXML))
    {
        result = (T) serializer.Deserialize(reader);
    }

    return result;
}

答案 4 :(得分:4)

无耻地复制 Generic deserialization of an xml string

    public static T DeserializeFromXmlString<T>(string xmlString)
    {
        var serializer = new XmlSerializer(typeof(T));
        using (TextReader reader = new StringReader(xmlString))
        {
            return (T) serializer.Deserialize(reader);
        }
    }