我想改变我的代码:
string path = @"c:\Directory\test.xml";
XmlSerializer s = new XmlSerializer(typeof(Car));
TextReader r = new StreamReader(path);
Car car = (Car)s.Deserialize(r);
r.Close();
代码将XML转换为字符串,然后将字符串转换为对象Car。
这可能吗?
答案 0 :(得分:233)
public static string XmlSerializeToString(this object objectInstance)
{
var serializer = new XmlSerializer(objectInstance.GetType());
var sb = new StringBuilder();
using (TextWriter writer = new StringWriter(sb))
{
serializer.Serialize(writer, objectInstance);
}
return sb.ToString();
}
public static T XmlDeserializeFromString<T>(this string objectData)
{
return (T)XmlDeserializeFromString(objectData, typeof(T));
}
public static object XmlDeserializeFromString(this string objectData, Type type)
{
var serializer = new XmlSerializer(type);
object result;
using (TextReader reader = new StringReader(objectData))
{
result = serializer.Deserialize(reader);
}
return result;
}
使用它:
//Make XML
var settings = new ObjectCustomerSettings();
var xmlString = settings.XmlSerializeToString();
//Make Object
var settings = xmlString.XmlDeserializeFromString<ObjectCustomerSettings>();
答案 1 :(得分:76)
如果您将XML存储在字符串变量中,则可以使用StringReader:
var xml = @"<car/>";
var serializer = new XmlSerializer(typeof(Car));
using (var reader = new StringReader(xml))
{
var car = (Car)serializer.Deserialize(reader);
}
答案 2 :(得分:14)
1-liner,将XML字符串text
和YourType
作为预期的对象类型。与其他答案差别不大,只是压缩到1行:
var result = (YourType)new XmlSerializer(typeof(YourType)).Deserialize(new StringReader(text));
答案 3 :(得分:6)
static T DeserializeXml<T>(string sourceXML) where T : class
{
var serializer = new XmlSerializer(typeof(T));
T result = null;
using (TextReader reader = new StringReader(sourceXML))
{
result = (T) serializer.Deserialize(reader);
}
return result;
}
答案 4 :(得分:4)
无耻地复制 Generic deserialization of an xml string
public static T DeserializeFromXmlString<T>(string xmlString)
{
var serializer = new XmlSerializer(typeof(T));
using (TextReader reader = new StringReader(xmlString))
{
return (T) serializer.Deserialize(reader);
}
}