我在android中有一个数组适配器,它将一组由SurveyQuestion对象组成的不同调查适应到列表视图中。
我最初遇到的问题是视图被回收,答案随处可见,但现在我已经解决了这个问题。
然而,每当我滚过问题时,当我向后滚动时,它会再次设置为默认答案。
如何阻止这种情况发生?
SurveyAdapter:
public class SurveyCTAdapter extends ArrayAdapter<SurveyQuestion> {
private final Context context;//needs a way to put in check boxes
private final List<SurveyQuestion> objects;
int[] rdioIDs;
public SurveyCTAdapter(Context context, int resource, List<SurveyQuestion> objects) {
super(context, resource, objects);
this.context = context;
this.objects = objects;
rdioIDs = new int[7];
rdioIDs[0] = R.id.r1;
rdioIDs[1] = R.id.r2;
rdioIDs[2] = R.id.r3;
rdioIDs[3] = R.id.r4;
rdioIDs[4] = R.id.r5;
rdioIDs[5] = R.id.r6;
rdioIDs[6] = R.id.r7;
}
public View getView(final int position, View convertView, ViewGroup parent){
LayoutInflater inflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
if (convertView == null) {
convertView = inflater.inflate(objects.get(position).rowID, null);
RadioGroup rdiogrp = (RadioGroup) convertView.findViewById(R.id.radioGroup1);
rdiogrp.setOnCheckedChangeListener(new OnCheckedChangeListener() {
@Override
public void onCheckedChanged(RadioGroup radio, int isChecked) {
View radioButton = radio.findViewById(isChecked);
int radioId = radio.indexOfChild(radioButton);
RadioButton btn = (RadioButton) radio.getChildAt(radioId);
String selection = (String) btn.getText();
SurveyQuestion question = (SurveyQuestion) radio.getTag();
int index = question.buttonNames.indexOf(selection);
if(index>=0){
question.currentAns=index;
Log.d("index",""+index);
}
notifyDataSetChanged();
}
});
}
TextView name = (TextView) convertView.findViewById(R.id.question);
String question = objects.get(position).question;
name.setText(question);
RadioGroup rdiogrp = (RadioGroup) convertView.findViewById(R.id.radioGroup1);
for(int i=0; i<objects.get(position).buttonNames.size(); i++){
RadioButton radioButton = (RadioButton) rdiogrp.findViewById(rdioIDs[i]);
radioButton.setText(objects.get(position).buttonNames.get(i));
}
RadioButton rdiobtn = (RadioButton) rdiogrp.findViewById(rdioIDs[objects.get(position).currentAns]);
rdiobtn.setChecked(true);
Log.d("position",""+position);
rdiogrp.setTag((objects).get(position));
return convertView;
}
}
和SurveyQuestion:
public class SurveyQuestion {
public String question;
public int rowID;
public ArrayList<String> buttonNames;
public HashMap<String, Integer> answerValue;
public int currentAns=0;
public boolean needTextBox;
public SurveyQuestion(String question, boolean b){
this.question=question;
this.needTextBox = b;
answerValue = new HashMap<String, Integer>();
}
public SurveyQuestion(String question, int ID){
this.question=question;
this.rowID = ID;
this.needTextBox = false;
answerValue = new HashMap<String, Integer>();
}
public SurveyQuestion(String question, int ID, ArrayList<String> names){
this.question=question;
this.rowID=ID;
this.buttonNames = names;
this.needTextBox = false;
answerValue = new HashMap<String, Integer>();
}
public int getScore(){
return answerValue.get(buttonNames.get(currentAns));
}
}
答案 0 :(得分:0)
我没有看到任何需要将您的问题存储在视图的标记中。我觉得这可能是问题的一部分。我在这种情况下通常做的是将一个Integer索引存储在一个可在ListView中操作的视图的标记中。在侦听器中,然后使用index标签使用getItem(int)
从ArrayAdapter中检索对象。