Question

我需要从我的单选按钮中获取值并添加到where子句的字符串中以更新将作为查询的一部分运行的where子句。我不确定如何将$ _POST ['answer']连接到第二个if块中的$ where

当前代码：

<form action="assignment.php" method="POST">
<input type="submit" name="start" value="start game">

<?php
$query = "SELECT `message`, `parentID`,`answerYesID`, `answerNoID`, `nodeID` FROM     `creature`";
$where = "";

if (isset($_POST['start'])){
  $where = "WHERE `nodeID` ='1'";
}


if (isset($_POST['submit']) && (isset ($_POST['answer']))){
        $where = "WHERE `nodeID` =";
}

$result = mysqli_query($dbconn, $query.$where);
$row = mysqli_fetch_assoc($result) ;
echo $row['message'];
?>

<input type="radio" name="answer" value="<?php echo $row['answerYesID'];?>">yes
<input type="radio" name="answer" value="<?php echo $row['answerNoID'];?>">no
<input type="submit" name="submit" value="submit">
</form>
</body>

</html>

Answer 1

$where = "WHERE `nodeID` = " . $_POST['answer'];

或如果您需要引号：

$where = "WHERE `nodeID` = '{$_POST['answer']}'";

Answer 2

你做对了，可能是你错过了creature和where之间的空格，试试：

if (isset($_POST['start']) && isset ($_POST['answer'])){
                                 #always a good idea to clean user input
   $where = " WHERE `nodeID` = '".mysqli_real_escape_string($dbconn,$_POST['answer'])."'";
            #^ left a space here
}

#You do not need the second isset().

$result = mysqli_query($dbconn, $query.$where);

Answer 3

首先，你所做的是一个非常糟糕的主意！您可以为单选按钮指定值，您可以根据无线电值更改查询中的ID。

要获得答案，请使用此

$result = mysqli_query($dbconn, $query.' '.$where);

我认为您需要$query和$where之间的空格

Answer 4

<form action="assignment.php" method="POST">
<input type="submit" name="start" value="start game">

<?php
$query = 'SELECT `message`, `parentID`,`answerYesID`, `answerNoID`, `nodeID` 
FROM     `creature`';
$where = ' ';

if (isset($_POST['start'])){
  $node = 1;
  $where .= 'WHERE `nodeID` = ?';
} elseif (isset($_POST['submit']) && (isset ($_POST['answer']))){
  $node = $_POST['answer'];
  $where .= 'WHERE `nodeID` = ?';
}
if ($stmt = $dbconn->prepare($query.$where)) {
  $stmt->bind_param('i', $name);
  $stmt->execute();
  while ($row = $stmt->fetch()) {
    echo $row['message'];
  }
}    
?>

<input type="radio" name="answer" value="<?php echo $row['answerYesID'];?>">yes
<input type="radio" name="answer" value="<?php echo $row['answerNoID'];?>">no
<input type="submit" name="submit" value="submit">
</form>
</body>

</html>

如何将单选按钮中的$ _POST值连接到PHP字符串？

4 个答案: