Question

我喜欢Sequel Pro在Mac上处理MySQL数据库。现在，我正试图用这个来创建一个视图：

CREATE VIEW '_view_userlist' AS 
SELECT u.userid,u.fullname,u.username,e.userid,e.listid,e.title,e.status 
FROM users u 
LEFT OUTER JOIN list e ON e.userid=u.userid 
WHERE u.status=1 AND e.status=1 
ORDER BY e.title ASC

但是我收到了这个错误：

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''_view_userlist' AS 
SELECT u.userid,u.fullname,u.username,e.userid,e.listid,e.t' at line 1

我不确定究竟是什么意思。当我尝试没有CREATE VIEW行的请求时，一切顺利。

我有MySQL 5.5.35。任何帮助o建议??

Answer 1

更改

CREATE VIEW '_view_userlist' AS

as

CREATE VIEW `_view_userlist` AS

或

CREATE VIEW _view_userlist AS

<强> DEMO

Answer 2

您应引用视图名称，以便正确的语法为

CREATE VIEW _view_userlist AS SELECT u.userid, ...

另请参阅手册页http://dev.mysql.com/doc/refman/5.5/en/create-view.html

尝试在MySQL中创建VIEW时出错

2 个答案: