Question

我试图用法线渲染一个简单的立方体。我使用以下代码初始化着色器。

void initShader(const char* vertexShaderPath, const char* fragmentShaderPath){
    cout<<"Initializing Shaders"<<endl<<"==="<<endl;
    cout<<"Vertex shader ";
    vs = loadShader(vertexShaderPath, GL_VERTEX_SHADER);
    cout<<"Fragment shader ";
    fs = loadShader(fragmentShaderPath, GL_FRAGMENT_SHADER);

    cout<<"Creating program: ";
    program = glCreateProgram();
    if(0==program) cout<< "Failed"<<endl; else cout<< "OK"<<endl;

    glAttachShader(program, vs);
    glAttachShader(program, fs);

    cout<<"Linking program: ";
    glLinkProgram(program); 
    GLint linkstatus = 0;
    glGetProgramiv(program, GL_LINK_STATUS, &linkstatus);
    if(GL_TRUE==linkstatus) cout<<"OK"<<endl; else cout<<"Failed" <<endl;

    cout<<endl<<endl<<"Memory status"<<endl<<"==="<<endl;

    mvpmat = glGetUniformLocation(program,"mvpMatrix");
    mvmat = glGetUniformLocation(program,"mvMatrix");
    normalmat = glGetUniformLocation(program,"normalMatrix");

    cout << "mvpMatrix: "<<mvpmat<<" mvMatrix: "<<mvmat<<" normalMatrix: " << normalmat<<endl;
}

最后一个cout语句的输出如下所示（编译或链接期间没有错误。）

mvpMatrix: 0 mvMatrix: -1 normalMatrix: 1

这是我的顶点着色器代码

uniform mat4 mvpMatrix;
uniform mat4 mvMatrix;
uniform mat3 normalMatrix;
attribute vec3 vertex;
attribute vec3 normal;
varying vec3 outNormal;
varying vec3 outPos;

void main(){
    gl_Position = mvpMatrix*vec4(vertex,1.0);
    outPos = (mvMatrix*vec4(vertex,1.0)).xyz;
    outNormal = normalize(normalMatrix*normal);
}

我在代码中使用了所有mvpMatrix，mvMatrix和normalMatrix。因此，我真的很困惑为什么getUniformLocation（）返回mvMatrix = -1？

Answer 1

如果您的片段着色器不使用outPos的输入，它将被优化掉。制服是在链接后定义的。因此片段和顶点着色器都计数。

glGetUniformLocation（）返回-1，即使在顶点着色器中使用

1 个答案: