电子邮件地址验证

时间：2014-04-26 10:35:54

标签： c# validation windows-phone-8 email-validation

所以我要做的是验证用户自己输入的电子邮件地址。

Microsoft开发人员网络提供了以下链接中验证电子邮件地址的示例代码：http://msdn.microsoft.com/en-us/library/01escwtf(v=vs.110).aspx

无论如何，我只是复制了代码并尝试使用它。但是我一直收到这个错误：

The type or namespace name 'IdnMapping' could not be found (are you missing a using directive or an assembly reference?)

我在网上找不到任何类似的问题，我无法想到会导致此错误的原因。

当然，当我们看到这样的错误时，首先想到的是我们忘记包含某些内容。

但是我在上面的页面中包含了所需的内容，因为我将在我的代码中显示。所以我真的无法理解问题本身的本质，开始寻找可能的解决方案。

我的代码：

using System;
using System.Globalization;
using System.Text.RegularExpressions;

public bool IsValidEmail(string strIn)
    {
        bool invalid = false;
        if (String.IsNullOrEmpty(strIn))
            return false;

        // Use IdnMapping class to convert Unicode domain names. 
        try
        {
            strIn = Regex.Replace(strIn, @"(@)(.+)$", this.DomainMapper,
                                  RegexOptions.None, TimeSpan.FromMilliseconds(200));
        }
        catch (RegexMatchTimeoutException)
        {
            return false;
        }

        if (invalid)
            return false;

        // Return true if strIn is in valid e-mail format. 
        try
        {
            return Regex.IsMatch(strIn,
                  @"^(?("")(""[^""]+?""@)|(([0-9a-z]((\.(?!\.))|[-!#\$%&'\*\+/=\?\^`\{\}\|~\w])*)(?<=[0-9a-z])@))" +
                  @"(?(\[)(\[(\d{1,3}\.){3}\d{1,3}\])|(([0-9a-z][-\w]*[0-9a-z]*\.)+[a-z0-9]{2,24}))$",
                  RegexOptions.IgnoreCase, TimeSpan.FromMilliseconds(250));
        }
        catch (RegexMatchTimeoutException)
        {
            return false;
        }
    }

    private string DomainMapper(Match match)
    {
        // IdnMapping class with default property values.
        IdnMapping idn = new IdnMapping();

        string domainName = match.Groups[2].Value;
        try
        {
            domainName = idn.GetAscii(domainName);
        }
        catch (ArgumentException)
        {
            invalid = true;
        }
        return match.Groups[1].Value + domainName;
    }

有关如何解决此问题或至少了解问题性质的任何建议。 在此先感谢：）

4 个答案:

答案 0 :(得分：2)

似乎这个类在.NET for Windows Phone上不存在。

This MSDN page表示它仅存在于.NET Framework 2.0+和.NET Framework Client Profile 3.5 SP1 +上。

答案 1 :(得分：1)

尝试这种符合RFC822的方法：

    var text = @"(?:(?:\r\n)?[ \t])*(?:(?:(?:[^()<>@,;:\\"".\[\] \000-\031]+(?:(?:(?:\r\n)?[ \t]
)+|\Z|(?=[\[""()<>@,;:\\"".\[\]]))|""(?:[^\""\r\\]|\\.|(?:(?:\r\n)?[ \t]))*""(?:(?:
\r\n)?[ \t])*)(?:\.(?:(?:\r\n)?[ \t])*(?:[^()<>@,;:\\"".\[\] \000-\031]+(?:(?:(
?:\r\n)?[ \t])+|\Z|(?=[\[""()<>@,;:\\"".\[\]]))|""(?:[^\""\r\\]|\\.|(?:(?:\r\n)?[ 
\t]))*""(?:(?:\r\n)?[ \t])*))*@(?:(?:\r\n)?[ \t])*(?:[^()<>@,;:\\"".\[\] \000-\0
31]+(?:(?:(?:\r\n)?[ \t])+|\Z|(?=[\[""()<>@,;:\\"".\[\]]))|\[([^\[\]\r\\]|\\.)*\
](?:(?:\r\n)?[ \t])*)(?:\.(?:(?:\r\n)?[ \t])*(?:[^()<>@,;:\\"".\[\] \000-\031]+
(?:(?:(?:\r\n)?[ \t])+|\Z|(?=[\[""()<>@,;:\\"".\[\]]))|\[([^\[\]\r\\]|\\.)*\](?:
(?:\r\n)?[ \t])*))*|(?:[^()<>@,;:\\"".\[\] \000-\031]+(?:(?:(?:\r\n)?[ \t])+|\Z
|(?=[\[""()<>@,;:\\"".\[\]]))|""(?:[^\""\r\\]|\\.|(?:(?:\r\n)?[ \t]))*""(?:(?:\r\n)
?[ \t])*)*\<(?:(?:\r\n)?[ \t])*(?:@(?:[^()<>@,;:\\"".\[\] \000-\031]+(?:(?:(?:\
r\n)?[ \t])+|\Z|(?=[\[""()<>@,;:\\"".\[\]]))|\[([^\[\]\r\\]|\\.)*\](?:(?:\r\n)?[
 \t])*)(?:\.(?:(?:\r\n)?[ \t])*(?:[^()<>@,;:\\"".\[\] \000-\031]+(?:(?:(?:\r\n)
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 \t])+|\Z|(?=[\[""()<>@,;:\\"".\[\]]))|\[([^\[\]\r\\]|\\.)*\](?:(?:\r\n)?[ \t])*
)(?:\.(?:(?:\r\n)?[ \t])*(?:[^()<>@,;:\\"".\[\] \000-\031]+(?:(?:(?:\r\n)?[ \t]
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[ \t]))*""(?:(?:\r\n)?[ \t])*)*:(?:(?:\r\n)?[ \t])*(?:(?:(?:[^()<>@,;:\\"".\[\] 
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\\.|(?:(?:\r\n)?[ \t]))*""(?:(?:\r\n)?[ \t])*)(?:\.(?:(?:\r\n)?[ \t])*(?:[^()<>
@,;:\\"".\[\] \000-\031]+(?:(?:(?:\r\n)?[ \t])+|\Z|(?=[\[""()<>@,;:\\"".\[\]]))|""
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\]]))|\[([^\[\]\r\\]|\\.)*\](?:(?:\r\n)?[ \t])*))*|(?:[^()<>@,;:\\"".\[\] \000-
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])*))*@(?:(?:\r\n)?[ \t])*(?:[^()<>@,;:\\"".\[\] \000-\031]+(?:(?:(?:\r\n)?[ \t
])+|\Z|(?=[\[""()<>@,;:\\"".\[\]]))|\[([^\[\]\r\\]|\\.)*\](?:(?:\r\n)?[ \t])*)(?
:\.(?:(?:\r\n)?[ \t])*(?:[^()<>@,;:\\"".\[\] \000-\031]+(?:(?:(?:\r\n)?[ \t])+|
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@,;:\\"".\[\]]))|\[([^\[\]\r\\]|\\.)*\](?:(?:\r\n)?[ \t])*))*(?:,@(?:(?:\r\n)?[
 \t])*(?:[^()<>@,;:\\"".\[\] \000-\031]+(?:(?:(?:\r\n)?[ \t])+|\Z|(?=[\[""()<>@,
;:\\"".\[\]]))|\[([^\[\]\r\\]|\\.)*\](?:(?:\r\n)?[ \t])*)(?:\.(?:(?:\r\n)?[ \t]
)*(?:[^()<>@,;:\\"".\[\] \000-\031]+(?:(?:(?:\r\n)?[ \t])+|\Z|(?=[\[""()<>@,;:\\
"".\[\]]))|\[([^\[\]\r\\]|\\.)*\](?:(?:\r\n)?[ \t])*))*)*:(?:(?:\r\n)?[ \t])*)?
(?:[^()<>@,;:\\"".\[\] \000-\031]+(?:(?:(?:\r\n)?[ \t])+|\Z|(?=[\[""()<>@,;:\\"".
\[\]]))|""(?:[^\""\r\\]|\\.|(?:(?:\r\n)?[ \t]))*""(?:(?:\r\n)?[ \t])*)(?:\.(?:(?:
\r\n)?[ \t])*(?:[^()<>@,;:\\"".\[\] \000-\031]+(?:(?:(?:\r\n)?[ \t])+|\Z|(?=[\[
""()<>@,;:\\"".\[\]]))|""(?:[^\""\r\\]|\\.|(?:(?:\r\n)?[ \t]))*""(?:(?:\r\n)?[ \t])
*))*@(?:(?:\r\n)?[ \t])*(?:[^()<>@,;:\\"".\[\] \000-\031]+(?:(?:(?:\r\n)?[ \t])
+|\Z|(?=[\[""()<>@,;:\\"".\[\]]))|\[([^\[\]\r\\]|\\.)*\](?:(?:\r\n)?[ \t])*)(?:\
.(?:(?:\r\n)?[ \t])*(?:[^()<>@,;:\\"".\[\] \000-\031]+(?:(?:(?:\r\n)?[ \t])+|\Z
|(?=[\[""()<>@,;:\\"".\[\]]))|\[([^\[\]\r\\]|\\.)*\](?:(?:\r\n)?[ \t])*))*\>(?:(
?:\r\n)?[ \t])*))*)?;\s*)".Replace(Environment.NewLine, "");

然后你可以这样做：

    var emailRegex = new Regex(text);

    var isValid = emailRegex.IsMatch("foo@bar.com");

说真的，这是正确的。

答案 2 :(得分：0)

使用MailAddress类，这是一段很好的代码。 原因是其他人已经为你做了正则表达式。

    public bool IsValid(string emailaddress)
    {
        try
        {
            MailAddress m = new MailAddress(emailaddress);
            return true;
        }
        catch (FormatException)
        {
            return false;
        }
    }

答案 3 :(得分：-2)

好的我现在刚刚找到这个，它似乎对我有用，我只是想分享它。

private bool IsValidEmail(string emailAddress)
{
        // Return true if emailAddress is in valid e-mail format.
        return Regex.IsMatch(emailAddress, @"^([0-9a-zA-Z]([-\.\w]*[0-9a-zA-Z])*@([0-9a-zA-Z][-\w]*[0-9a-zA-Z]\.)+[a-zA-Z]{2,9})$");
}
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