Question

我正在制作猜谜游戏。一切正常，但我有一个问题。我第一次要求一个号码它正确地说我是高还是低，但第二次没有说什么..

这是我的服务器和客户端代码：

 public class ServerNum
    {
    public static void main(String[] args) throws IOException
    {
        adivinarNum juego = new adivinarNum();
        ServerSocket socket = null;
        Socket client = null;
        String resultado;
        boolean correcto = false;
        int intentos;

                try{
                    socket = new ServerSocket(1234);

                }catch(IOException ioe)

                {
                    System.err.println(ioe);
                    return;
                }
                    System.out.println("El servidor sigue funcionando...");
                    client = socket.accept();
                    System.out.println("El cliente se ha conectado");
                    DataInputStream in = new DataInputStream(new BufferedInputStream(client.getInputStream()));
                    DataOutputStream out = new DataOutputStream(new BufferedOutputStream(client.getOutputStream()));
        while(!correcto)
            {
                intentos = in.readInt();
                resultado = juego.adivinar(intentos);
                correcto = juego.getCorrecto();
                out.writeUTF(resultado);
                out.writeBoolean(correcto);
                out.flush();
            if(correcto == false){
                client = socket.accept();
                intentos = in.readInt();
                resultado = juego.adivinar(intentos);
                correcto = juego.getCorrecto();
                out.writeUTF(resultado);
                out.writeBoolean(correcto);
                out.flush();
              }
            else{
                client.close();
                socket.close();
                }

           }
        }
    }


        public class ClientNum
        {
         public static void main(String[] args) throws IOException
         {
            System.out.println("This is Number Guessing Game. \nChoose any number between 1 to 1000 : ");
           Scanner keyboard = new Scanner(System.in);
           int attempt = 0;
           try
           {
             attempt = keyboard.nextInt();
             if(attempt < 1 || attempt > 999)
             {
               System.out.println("Your number is too large/small, please make a guess between 1 to 1000");
               attempt = keyboard.nextInt();
              }
            }
        catch(NumberFormatException nfe)
        {
          System.out.println("Just choose numbers! Try again");
          attempt = keyboard.nextInt();
        }

        try
                {
                    Socket server = new Socket("localhost", 1234);
                    System.out.println("Connecting...");

                    DataOutputStream out = new DataOutputStream(new BufferedOutputStream(server.getOutputStream()));
                    DataInputStream in = new DataInputStream(new BufferedInputStream(server.getInputStream()));

                    out.writeInt(attempt);
                    out.flush();
                    System.out.println("Our server is still running...");
                    String result = in.readUTF();
                    boolean correct = in.readBoolean();
                    System.out.println(result);


                    while (!correct){
                            attempt = keyboard.nextInt();
                            out.writeInt(attempt);
                            out.flush();
                            System.out.println("Our server is still running...");
                            result = in.readUTF();
                            System.out.println(result);
                            correct = in.readBoolean();
                     }

                        server.close();
                        System.out.println("Finish. Thank you");
                        System.exit(0);

                }catch(IOException ioe){
                    System.err.println(ioe);
                }
            }
        }

我将不胜感激任何帮助！谢谢你！

Answer 1

socket.accept用于接受与客户端的连接。这意味着它用于开始与客户端通信，因此，每个连接只需要调用一次。此外，您的客户端一旦得到正确的答案就会断开连接，然后到达其main()方法的末尾，这意味着程序在那里结束。

您应该设计程序，以便建立连接，然后在while循环内播放游戏代码，通常称为“游戏循环”，直到用户不再希望播放。当用户不再希望播放时，允许循环结束，然后让它关闭与服务器的连接，以便应用程序可以正常关闭。

应该注意的是accept方法具有与之相关的效率开销，因此如果您不必经常调用它，程序将更有效地运行。

Java猜测游戏服务器 - 客户端

1 个答案: