Question

我有一个UIView是menuiitems，这些菜单项是动态创建的，我在每个uiview标签上加1，但是当我想在用户点击菜单项时检索uiview标签值我得到一个不同的标签号。

我想检索存储了id的标记，以便我可以将该id发布到php脚本。

我在设置标签时如何检索标签？

- (void)handleSingleTap:(UITapGestureRecognizer *)recognizer {
    UIView *tempView = recognizer.view;
    NSNumber *tag = [NSNumber numberWithInt:tempView.tag];
    int idCat = [tag intValue];
    NSLog(@"TAG %d", idCat);

    NSURLRequest *request =
    [NSURLRequest requestWithURL:[NSURL URLWithString:[NSString stringWithFormat:
     @"http://localhost:8888/MAMP/WHFC/SubCategories.php?categoryid=%d", idCat]]];

    int i = 0;

    NSError *e;
    NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:&e];
    NSArray *arrCategoryList =
    [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingAllowFragments error:&e];

    UIViewController *viewController = [[UIViewController alloc] init];
    viewController.view.backgroundColor = [UIColor whiteColor];

    UIView *uiView = [[UIView alloc] init];
    [uiView setFrame:CGRectMake(0, 480, 320, 480)];
    [uiView setBackgroundColor:[UIColor grayColor]];

    viewController.view = uiView;

    UITableView *uiTableView = [[UITableView alloc] init];
    [uiTableView setFrame:CGRectMake(0, 0, 320, 480)];

    [uiView addSubview:uiTableView];

    [self presentViewController:viewController animated:YES completion:nil];
}

这是在另一个视图中创建菜单项的代码：

NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString: @"http://localhost:8888/MAMP/WHFC/categories.php"]];

int i = 0;

NSError *e;
NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:&e];
NSArray *arrCategoryList = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingAllowFragments error:&e];
for(NSDictionary *dictCategory in arrCategoryList)
{
    NSString *strCategoryId = [dictCategory objectForKey:@"CategoryId"];
    NSString *strCategoryName = [dictCategory objectForKey:@"Name"];
    NSLog(@"%@ : %@",strCategoryId,strCategoryName);

    UIView *linkMenu = [[UIView alloc] init];
    [linkMenu setFrame:CGRectMake(10, i+1, 300, 35)];
    linkMenu.tag = [NSString stringWithFormat:@"%d", strCategoryId];
    linkMenu.layer.zPosition = 1;
    [viewSlide3 addSubview:linkMenu];
    [linkMenu setBackgroundColor:[UIColor blueColor]];
    linkMenu.backgroundColor = [UIColor colorWithRed:0 green:0 blue:0 alpha:.9];

    UITapGestureRecognizer *singleFingerTap =
    [[UITapGestureRecognizer alloc] initWithTarget:self
                                            action:@selector(handleSingleTap:)];
    [linkMenu addGestureRecognizer:singleFingerTap];

    UILabel *labelMenu = [[UILabel alloc] init];
    [labelMenu setFrame:CGRectMake(20, 0, 300, 35)];
    [labelMenu setFont:[UIFont systemFontOfSize:16]];
    [labelMenu setTextColor:[UIColor whiteColor]];
    [linkMenu addSubview:labelMenu];
    [labelMenu setText:strCategoryName];
    i = i + 35 + 1;
}

Answer 1

如果你有一个UIView让我们说放在里面的所有其他菜单项也是UIViews让我们说B，C和D那么很可能是识别器。你回来了A无论B，C或D中的哪一个被按下。

将此内容写入handleSingleTap函数：

CGPoint touchPoint=[gesture locationInView:scrollView];
for(UIView * subView in myView ) //here myView should be the superView A where you have added all the menu item view B, C, and D
{
  if(CGRectContainsPoint(subView.bounds, touchPoint))
  {
    NSNumber *tag = [NSNumber numberWithInt:subView.tag];
  }
}

该标记变量将包含您需要的最终标记。

使用int值设置UIView标记但不能返回相同的标记值

1 个答案: