我需要一个SQL函数来计算年龄。它必须准确并涵盖所有角落情况 它适用于婴儿的医院病房,因此30分钟的年龄是常见的情况。
我查看了其他答案但找不到处理所有案例的答案。
例如:
年龄应为0岁,0个月,0天,0小时, 11分钟
如果有人能够提供该功能的最终和最终版本,那就太棒了。
(我担心使用DateDiff的简单解决方案不够好。如更受欢迎的question 中所述:" Datediff功能无法处理年份边界很好......"
答案 0 :(得分:2)
此查询将以分钟为单位为您提供日期差异
select datediff(mi, '2014-04-23 05:23:59.660',getdate())
然后,您只需为minutes/60
和hours
计算minutes mod 60
的{{1}} 1>
minutes
答案 1 :(得分:1)
我们可以使用DATEDIFF
来获取年,月和日差异,然后使用简单除法来表示秒,分和小时差异。
我已使用@CurrentDate
重新创建原始请求,但@CurrentDate = GETDATE()
将在执行时返回年龄。
DECLARE @BirthDate DATETIME
DECLARE @CurrentDate DATETIME
SET @BirthDate = '2014-04-29 12:59:00.000'
SET @CurrentDate = '2014-04-29 13:10:23.000'
DECLARE @DiffInYears INT
DECLARE @DiffInMonths INT
DECLARE @DiffInDays INT
DECLARE @DiffInHours INT
DECLARE @DiffInMinutes INT
DECLARE @DiffInSeconds INT
DECLARE @TotalSeconds BIGINT
-- Determine Year, Month, and Day differences
SET @DiffInYears = DATEDIFF(year, @BirthDate, @CurrentDate)
IF @DiffInYears > 0
SET @BirthDate = DATEADD(year, @DiffInYears, @BirthDate)
IF @BirthDate > @CurrentDate
BEGIN
-- Adjust for pushing @BirthDate into future
SET @DiffInYears = @DiffInYears - 1
SET @BirthDate = DATEADD(year, -1, @BirthDate)
END
SET @DiffInMonths = DATEDIFF(month, @BirthDate, @CurrentDate)
IF @DiffInMonths > 0
SET @BirthDate = DATEADD(month, @DiffInMonths, @BirthDate)
IF @BirthDate > @CurrentDate
BEGIN
-- Adjust for pushing @BirthDate into future
SET @DiffInMonths = @DiffInMonths - 1
SET @BirthDate = DATEADD(month, -1, @BirthDate)
END
SET @DiffInDays = DATEDIFF(day, @BirthDate, @CurrentDate)
IF @DiffInDays > 0
SET @BirthDate = DATEADD(day, @DiffInDays, @BirthDate)
IF @BirthDate > @CurrentDate
BEGIN
-- Adjust for pushing @BirthDate into future
SET @DiffInDays = @DiffInDays - 1
SET @BirthDate = DATEADD(day, -1, @BirthDate)
END
-- Get number of seconds difference for Hour, Minute, Second differences
SET @TotalSeconds = DATEDIFF(second, @BirthDate, @CurrentDate)
-- Determine Seconds, Minutes, Hours differences
SET @DiffInSeconds = @TotalSeconds % 60
SET @TotalSeconds = @TotalSeconds / 60
SET @DiffInMinutes = @TotalSeconds % 60
SET @TotalSeconds = @TotalSeconds / 60
SET @DiffInHours = @TotalSeconds
-- Display results
SELECT @DiffInYears AS YearsDiff,
@DiffInMonths AS MonthsDiff,
@DiffInDays AS DaysDiff,
@DiffInHours AS HoursDiff,
@DiffInMinutes AS MinutesDiff,
@DiffInSeconds AS SecondsDiff
答案 2 :(得分:0)
它会在几秒钟内select datediff(s, '2014-04-23 05:23:59.660',getdate())