我正在尝试在CakePHP中进行Ajax调用。第一个调用工作正常,它使用另一个Ajax提交按钮呈现视图。以下代码在第一个视图中:
echo $this->Js->submit('LOAD COMMENTS',array(
'url'=>array(
'controller'=>'Nominees',
'action'=>'load_comments'
),
'before'=>$this->Js->get('#sending')->effect('fadeIn'),
'success'=>$this->Js->get('#sending')->effect('fadeOut'),
'update'=>'#comments'
));
echo $this->Form->end();
在Nominees控制器中我有
public $components = array('RequestHandler');
/*Load comments for the nominee using ajax*/
public function load_comments(){
if(!empty($this->request->data)){
/* Demoting Irrelevant comments.
Only triggered if the demote comment button is clicked.*/
if(isset($this->request->data['Nominee']['comment_nominee_id'])){
$comment_id = $this->request->data['Nominee']['comment_nominee_id'];
$this->Nominee->updateAll(
array('Nominee.status' =>0),
array('Nominee.id'=>$comment_id));
}
$userNumber = $this->request->data['Nominee']['number'];
$award_id = $this->request->data['Nominee']['award'];
$dt = date('Y');
$nominationInfor = $this->Nominee->find('all',array(
'conditions' => array('Nominee.reg_number'=>$studNumber,'Nominee.year'=>$dt,'Nominee.award_id'=>$award_id,'Nominee.status'=>1),
'recursive' => -1
));
if(empty($nominationInfor)){
$this->Session->setFlash(__('No Nomination Information Available.'));
$this->redirect(array('action' => 'choose_category'));
}
$this->set(compact('nominationInfor','userNumber','award_id'));
if($this->request->isAjax()){
$this->render('load_comments','ajax');
}
}
}
Load_comments,即被调用的视图,有一个Ajax按钮,其视图代码如下所示:
echo $this->Js->submit('Demote Comment',array(
'url'=>array(
'controller'=>'AwardNominees',
'action'=>'load_comments'
),
'before'=>$this->Js->get('#demot')->effect('fadeIn'),
'success'=>$this->Js->get('#demot')->effect('fadeOut'),
'update'=>'#comments'
));
echo $this->Form->end();
单击“降级注释”按钮时,
debug($this->request->isAjax());
返回false,但如果单击LOAD COMMENTS
debug($this->request->isAjax());
返回true。这个想法是当点击加载注释时,加载注释然后单击Demote Comment(这是注释的按钮)我想做一个Ajax调用删除其注释。非常感谢您的帮助。
答案 0 :(得分:0)
我终于弄明白我在参考this
时出错了在我的提交按钮上,我使用我的回调函数在数组中添加了'buffer'=> false,因此最终提交如下所示
echo $this->Js->submit('Demote Comment',array(
'url'=>array(
'controller'=>'AwardNominees',
'action'=>'load_comments'
),
'before'=>$this->Js->get('#demot')->effect('fadeIn'),
'success'=>$this->Js->get('#demot')->effect('fadeOut'),
'update'=>'#comments',
'buffer' => false
));
我将不同的id添加到我创建的表单中。这使我的代码按预期工作。 : - )