Question

这是我到目前为止的程序，我想知道，如何将每周的工资加起来以及如何找到平均值：

Chelsea_Salaries_2014 = {'Jose Mourinho':[53, 163500, 'Unknown']}
Chelsea_Salaries_2014['Eden Hazard']=[22, 185000, 'June 2017']
Chelsea_Salaries_2014['Fernando Torres']=[29, 175000, 'June 2016']
Chelsea_Salaries_2014['John Terry']=[32, 175000, 'June 2015']
Chelsea_Salaries_2014['Frank Lampard']=[35, 125000, 'June 2014']
Chelsea_Salaries_2014['Ashley Cole']=[32, 120000, 'June 2014']
Chelsea_Salaries_2014['Petr Cech']=[31, 100000, 'June 2016']
Chelsea_Salaries_2014['Gary Cahill']=[27, 80000, 'June 2017']
Chelsea_Salaries_2014['David Luiz']=[26, 75000, 'June 2017']
Chelsea_Salaries_2014['John Obi Mikel']=[26, 75000, 'June 2017']
Chelsea_Salaries_2014['Nemanja Matic']=[25, 75000, 'June 2019']
Chelsea_Salaries_2014['Marco Van Ginkel']=[20, 30000, 'June 2018']
Chelsea_Salaries_2014['Ramires']=[26, 60000, 'June 2017']
Chelsea_Salaries_2014['Oscar']=[21, 67500, 'June 2017']
Chelsea_Salaries_2014['Lucas Piazon']=[19, 15000, 'June 2017']
Chelsea_Salaries_2014['Ryan Bertrand']=[23, 35000, 'June 2017']
Chelsea_Salaries_2014['Marko Marin']=[27, 35000, 'June 2017']
Chelsea_Salaries_2014['Cesar Azpilicueta']=[23, 55000, 'June 2017']
Chelsea_Salaries_2014['Branislav Ivanovic']=[29, 67500, 'June 2016']
Chelsea_Salaries_2014['Ross Turnbull']=[22, 17000, 'June 2017']
Chelsea_Salaries_2014['Demba Ba']=[28, 65000, 'June 2016']
Chelsea_Salaries_2014['Oriol Romeu']=[22, 15000, 'June 2015']

Total_Wages_Week = Chelsea_Salaries_2014.count('2')
print(str(Total_Wages_Week))

Answer 1

你可以这样做：

>>> print sum(i[1] for i in Chelsea_Salaries_2014.values())/len(Chelsea_Salaries_2014)
82295

Answer 2

从版本3.4开始，mean模块中有statistics方法。所以你可以这样做：

from statistics import mean
average_salary = mean((i[1] for i in Chelsea_Salaries_2014.values()))

可以使用sum函数找到总和：

salary_sum = sum(i[1] for i in Chelsea_Salaries_2014.values())

写一个循环，累计你字典中所有玩家的每周工资。打印出每周工资总额

2 个答案: