Python:鼠标单击时返回坐标信息

时间:2014-04-22 12:11:18

标签: python matplotlib user-interaction

我想在python中显示图像,并允许用户单击特定像素。然后我想使用x和y坐标来执行进一步的计算。

到目前为止,我一直在使用事件选择器:

def onpick1(event):
    artist = event.artist
    if isinstance(artist, AxesImage):
        mouseevent = event.mouseevent
        x = mouseevent.xdata
        y = mouseevent.ydata
        print x,y

xaxis = frame.shape[1]
yaxis = frame.shape[0]
fig = plt.figure(figsize=(6,9))
ax = fig.add_subplot(111)
line, = [ax.imshow(frame[::-1,:], cmap='jet', extent=(0,xaxis,0,yaxis), picker=5)]
fig.canvas.mpl_connect('pick_event', onpick1)
plt.show()

现在我真的很喜欢function onpick1()return x and y,所以我可以在plt.show()之后使用它来执行进一步的计算。

有什么建议吗?

1 个答案:

答案 0 :(得分:2)

GUI编程的一个好教训就是面向对象。你现在的问题是你有一个异步回调,你想保持它的值。您应该考虑将所有内容组合在一起,例如:

class MyClickableImage(object):
    def __init__(self,frame):
        self.x = None
        self.y = None
        self.frame = frame
        self.fig = plt.figure(figsize=(6,9))
        self.ax = self.fig.add_subplot(111)
        xaxis = self.frame.shape[1]
        yaxis = self.frame.shape[0]
        self.im = ax.imshow(self.frame[::-1,:], 
                  cmap='jet', extent=(0,xaxis,0,yaxis), 
                  picker=5)
        self.fig.canvas.mpl_connect('pick_event', self.onpick1)
        plt.show()

    # some other associated methods go here...

    def onpick1(self,event):
        artist = event.artist
        if isinstance(artist, AxesImage):
            mouseevent = event.mouseevent
            self.x = mouseevent.xdata
            self.y = mouseevent.ydata

现在,当您点击某个点时,它会设置您班级的xy属性。但是,如果您想使用xy执行计算,则可以让onpick1方法执行这些计算。