我是java新手,这也是我第一次在这里提问。 我必须使用一个存储输入数据的数组编写程序。我试图提示70到90之间的六个值。现在它只允许我输入三个数字,然后其他三个是零,但我无法弄清楚要修改的内容。这就是我所拥有的:
Scanner scanner = new Scanner(System.in);
int[] values = new int[6];
int i;
int sum = 0;
for (i = 0; i < values.length; i++) {
System.out.print("Enter a number between 70 and 90: ");
values[i] = scanner.nextInt();
i++;
if (i == 6) {
break;
}
sum = sum + values[i];
}
double average = (sum / 6);
Arrays.sort(values);
System.out.println(Arrays.toString(values));
System.out.println("Average is " + average);
Arrays.sort(values);
int min = values[0];
System.out.println("Minimum is " + min);
System.out.println("Its index is " + Arrays.asList(values).indexOf(min));
int max = values[values.length - 1];
System.out.println("Maximum is " + max);
System.out.println("The difference between the largest and smallest elements is "
+ (max - min));
scanner.close();
答案 0 :(得分:4)
您在循环中递增i
两次。
for(i=0; i<values.length; i++){ // <-- this is a good place for it.
System.out.print("Enter a number between 70 and 90: ");
values[i] = scanner.nextInt();
// i++; // only need one.
// if(i == 6){
// break;
// }
sum += values[i]; // <-- you can use += too
}
当然,你真的想要它也可能 -
// This also declares i at more restricted scope.
for (int i=0; i < values.length; ) { // <-- remove i increment.
System.out.print("Enter a number between 70 and 90: ");
int value = scanner.nextInt();
if (value < 70 || value > 90) {
continue; // <-- will not increment i.
// because I removed the increment in the for loop.
// also could have done --i, then continue;
}
values[i] = value;
sum += value; // <-- you can use += too
i++; // <-- after adding to the sum.
}
答案 1 :(得分:2)
您在每次迭代时将循环索引递增两次
for(i=0; i<values.length; i++){
System.out.print("Enter a number between 70 and 90: ");
values[i] = scanner.nextInt();
i++;
if(i == 6){
break;
}
sum = sum + values[i];
}
删除for循环中的i ++语句,它应该可以工作。此外,if(i == 6)then break语句是不必要的,因为当“i小于values.length”条件不再为真时,循环将终止。
所以你的循环应该是
for(i=0; i<values.length; i++){
System.out.print("Enter a number between 70 and 90: ");
values[i] = scanner.nextInt();
sum = sum + values[i];
}