Question

我正试图从GSM调制解调器发送消息。我可以提交AT命令，响应是确定，没有任何错误。但问题是我无法发送消息或阅读消息。

我已经实现了3个功能：

连接到端口
阅读短信
发送短信
把手

1。连接到端口：

    Private Sub BtnConnect_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles BtnConnect.Click
            If SerialPort1.IsOpen Then
                SerialPort1.Close()
                BtnConnect.Text = "Connect"
            Else
                Try
                    With SerialPort1
                        .PortName = Trim(Mid(ComboBox1.Text, 1, 5))
                        .BaudRate = 9600
                        .Parity = IO.Ports.Parity.None
                        .DataBits = 8
                        .StopBits = Ports.StopBits.One
                        .Handshake = Ports.Handshake.None
                        .RtsEnable = True
                        .DtrEnable = True
                        .Open()
                        .WriteLine("AT+CNMI=1,2,0,0,0" & vbCrLf) 'send whatever data that it receives to serial port  
                    End With
                    BtnConnect.Text = "Disconnect"
                Catch ex As Exception
                    BtnConnect.Text = "Connect"
                    MsgBox(ex.Message)
                End Try
            End If

        End Sub

2。阅读短信

      Private Sub btn_read_Click(ByVal sender As Object, ByVal e As EventArgs) Handles btn_read.Click
            Try
                SerialPort1.WriteLine("AT" & vbCrLf) 'is modem okay?
                Thread.Sleep(1000)

                SerialPort1.WriteLine("AT+CMGF=1" & vbCrLf) 'To format SMS as a TEXT message
                Thread.Sleep(1000)

                SerialPort1.WriteLine("AT+CPMS=""SM""" & vbCrLf) ' Select SIM storage
                Threading.Thread.Sleep(1000)

                SerialPort1.WriteLine("AT+CMGL=""REC UNREAD""" & vbCrLf) 'read unread messages
                Threading.Thread.Sleep(1000)

                SerialPort1.WriteLine("AT+CMGL=""ALL""" & vbCrLf) 'print all message
                Threading.Thread.Sleep(1000)
            Catch ex As Exception
                MsgBox(ex.Message)
            End Try
        End Sub

第3。发送短信

 Private Sub btn_send_Click(ByVal sender As Object, ByVal e As EventArgs) Handles btn_send.Click
        Try
            With SerialPort1
                .WriteLine("AT" & vbCrLf)
                Threading.Thread.Sleep(1000)
                .WriteLine("AT+CMGF=1" & vbCrLf) 'Instruct the GSM / GPRS modem to operate in SMS text mode
                Threading.Thread.Sleep(1000)
                .WriteLine("AT+CMGS=""9802100355""" & vbCr) 'sender ko no. rakhne ho tyo txtnumber ma 
                Threading.Thread.Sleep(1000) 'thapeko
                .WriteLine("This is test message" & vbCrLf & Chr(26)) 'txtmessage automatic huna parchha haina?

            End With


        Catch ex As Exception
            MsgBox(ex.Message)
        End Try
    End Sub

4。处理串行端口中收到的数据

Private Sub serialport1_datareceived(ByVal sender As Object, ByVal e As System.IO.Ports.SerialDataReceivedEventArgs) Handles SerialPort1.DataReceived
    'Pause while all data is read
    System.Threading.Thread.Sleep(300)
    rcvdata = SerialPort1.ReadExisting()
    MsgBox(rcvdata, , "Response From AT")
    rcvdata = ""

End Sub

我在哪里错过了什么？发送短信时，我收到CMS 500错误。使用调制解调器的软件，我能够读取和发送短信。但我需要在我的软件中实现自己的功能。

Answer 1

此错误可能有多种原因。首先检查你的网络。第二组使用AT命令发送消息服务中心号码并保存此设置。希望这会对你有所帮助

Answer 2

在第二个函数中，您可以尝试声明一个字符串变量来接收数据，如下所示：

With serialport1
    rcvdata=""
    .Write(All AT commands)
    Threading.Thread.Sleep(1000)
    Msgbox(rcvdata.Tostring)
End With

您可以向datareceived添加处理程序以读取所有字节：

Dim entrada As String = " "
Dim numeros As Integer = SerialPort1.BytesToRead
For i As Integer = 1 To numeros
    entrada&= Chr(SerialPort1.ReadChar)
Next
chama(entrada)
Private Sub chama(ByVal dados As String)
    rcvdata &= dados
End Sub

Answer 3

AT+CMGS=""9802100355"

您的电话号码错误，这就是您收到错误500的原因，您需要在前面输入包括0在内的完整电话号码。

从GSM调制解调器发送和接收SMS

3 个答案: