Question

我有这个代码使用.get()函数从Tkinter条目中检索输入：

from Tkinter import *
def access():
    access_window = Toplevel(root)
    access_window.title("Access a Contact")
    Label(access_window, text="Enter a first name: ").grid(row=0, sticky=W+E)
    access_key = Entry(access_window, width=8)
    access_key.grid(row=1, sticky=W+E)
    Button(access_window, text="Submit", command=lambda: get_info(str(access_key.get("1.0", "end")))).grid(row=2, sticky=W+E)

但是当我点击按钮时，我收到此错误：

Exception in Tkinter callback
Traceback (most recent call last):
  File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/lib-tk/Tkinter.py", line 1470, in __call__
    return self.func(*args)
  File "/Users/stephenhjb/Documents/First tkinter", line 17, in <lambda>
    Button(access_window, text="Submit", command=lambda: get_info(str(access_key.get("1.0", "end")))).grid(row=2, sticky=W+E)
TypeError: get() takes exactly 1 argument (3 given)

为什么会这样？

Answer 1

Entry对象的方法.get（）不接受任何参数。它用于获取Entry对象中的值。（获取输入字段的当前内容）。不要将此.get（）与Python的内置get（）混淆。

字体：http://effbot.org/tkinterbook/entry.htm

功能不起作用

1 个答案: