我是Symfony2的新手,我只是想尝试一些东西来学习Symfony2。 目前,我有一些控制器可以完成一些简单的任务。例如一个简单的crud控制器。
我的网页扩展了base.html.twig文件并将其块插入其中。现在我想在我的基本文件中添加一个登录部分,因为我希望能够在每个页面上登录。我正在考虑使用formbuilder,但这是php代码,不能在html.twig文件中。我绝对不知道如何处理这个问题。有人能把我推向正确的方向,给我一些有用的例子吗?
提前感谢
操作:
public function loginFormAction(Request $request){
// create a task and give it some dummy data for this example
$message = "";
$account = new Account();
$account->setEmail('login@login.nl');
$form = $this->createFormBuilder($account)
->add('email', 'text')
->add('wachtwoord', 'text')
->add('login', 'submit')
->getForm();
$form->handleRequest($request);
if ($_POST != null && $_POST['form']['email'] != null) {
$repository = $this->getDoctrine()->getRepository('AcmeBlogBundle:Account');
$email =$_POST['form']['email'];
$wachtwoord =$_POST['form']['wachtwoord'];
$foundAccount = $repository->findOneByemail($email);
if (!$foundAccount) {
$message = "Ingevuld email en wachtwoord komen niet overeen.";
}else if($foundAccount->getWachtwoord() == $wachtwoord){
$session = $request->getSession();
$session->set('name', $foundAccount->getVoornaam() . " " . $foundAccount->getAchternaam());
$session->set('email', $foundAccount->getEmail());
//return $this->redirect($this->generateUrl('melding', array('melding' => 'mooiman')));
//return $this->render('AcmeBlogBundle:Account:melding.html.twig', array('melding' => 'Hallo, '.$foundAccount->getVoornaam() . " " . $foundAccount->getAchternaam()));
$message = 'Hallo, '.$foundAccount->getVoornaam() . " " . $foundAccount->getAchternaam();
$form = $this->createFormBuilder()
->add('logout', 'submit')
->getForm();
return $this->render('AcmeBlogBundle:Account:login.html.twig', array('form'=> $form->createView(), 'message' => $message));
}else{
$message = "Ingevuld email en wachtwoord komen niet overeen.";
}
}
return $this->render('AcmeBlogBundle:Account:login.html.twig', array('form'=> $form->createView(), 'message' => $message));
}
public function logoutFormAction(Request $request){
// create a task and give it some dummy data for this example
$session = $request->getSession();
$message = 'Hallo, '.$session->get('name');
$form = $this->createFormBuilder()
->add('logout', 'submit')
->getForm();
$form->handleRequest($request);
if ($_POST != null) {
$account = new Account();
$account->setEmail('login@login.nl');
$form = $this->createFormBuilder($account)
->add('email', 'text')
->add('wachtwoord', 'text')
->add('login', 'submit')
->getForm();
$session->set('name', null);
$session->set('email', null);
$message = "U bent nu uitgelogd";
}
return $this->render('AcmeBlogBundle:Account:login.html.twig', array('form'=> $form->createView(), 'message' => $message));
}
Base.html.twig:
{% if(app.session.get('name') == null) %}
{{ render(controller('AcmeBlogBundle:Account:loginForm')) }}
{% else %}
{{ render(controller('AcmeBlogBundle:Account:logoutForm')) }}
{% endif %}
答案 0 :(得分:1)
您可以在模板中包含其他控制器/操作的整个输出。只需将其包含在您的taplate中:
<div id="sidebar">
{{ render(controller('YourBundle:User:login')) }}
</div>
这会将YourBundle / UserController / loginAction的整个输出注入#sidebar div。请记住,YourBundle / UserController / loginAction模板不能扩展其他树枝模板,并且应该很简单。
您可以在此处了解有关嵌入控制器的更多信息http://symfony.com/doc/current/book/templating.html#embedding-controllers
[实施例]:
表单操作:
/**
* @Route("/contact", name="contact")
*/
public function contactAction(Request $request){
$form = $this->createFormBuilder()
->setAction($this->generateUrl('contact'))
->add('email', 'email', array(
'constraints' => array(
new \Symfony\Component\Validator\Constraints\Email()
)
))
->add('add', 'submit')
->getForm()
;
if ($request->getMethod() == 'POST') {
$form->handleRequest($request);
if ($form->isValid()) {
//do whatever you want and redirect
return $this->redirect($this->generateUrl('homepage'));
}else{
// this must be a full page (extending from base tamplate)
// that show form and errors
return $this->render(
'YourBundle:ControllerName:contact_faild.html.twig',
array('form' => $form->createView())
);
}
}
return $this->render(
'YourBundle:ControllerName:contact.html.twig',
array('form' => $form->createView())
);
}
表格中必须有操作网址&#34; - &gt; setAction($ this-&gt; generateUrl(&#39; contact&#39;))&#34;因为表单应该在单独的请求上处理。
接下来是表单模板(YourBundle:ControllerName:contact.html.twig):
{{ form(form) }}
然后我们需要一个额外的模板来在出现问题时显示表单错误。这应该扩展基本模板,并可能覆盖第一次出现表单的位置 错误形式的表单(YourBundle:ControllerName:contact_faild.html.twig):
{% extends '::base.html.twig' %}
{% block sidebar -%}
{{ form(form) }}
{% endblock sidebar %}
基础teplate:
(...)
{% block sidebar %}
<div id="sidebar">
{{ render(controller('ClickAdUserBundle:User:contact')) }}
</div>
{% endblock %}
(...)
答案 1 :(得分:0)
阅读this 你会找到一些html / twig代码,把它放在“login.html.twig”中并把它包含在你想要的地方
答案 2 :(得分:0)
如果您对Symfony2完全不熟悉,我可以建议symfony2 symblock tutorial
在创建一个小博客时,您将使用Doctrine 2,创建表单并设计它们,Twig Layouts以及所有其他内容。
从示例中获取,您将在控制器中创建表单,如此
// src/Blogger/BlogBundle/Controller/PageController.php
public function contactAction()
{
$enquiry = new Enquiry(); //This creates an Instance of the Entity you need for the form
$form = $this->createForm(new EnquiryType(), $enquiry);
$request = $this->getRequest();
if ($request->getMethod() == 'POST') {
$form->bindRequest($request);
if ($form->isValid()) {
// Perform some action, such as sending an email
// Redirect - This is important to prevent users re-posting
// the form if they refresh the page
return $this->redirect($this->generateUrl('BloggerBlogBundle_contact'));
}
}
return $this->render('BloggerBlogBundle:Page:contact.html.twig', array(
'form' => $form->createView()
));
}
和.html.twig的形式看起来像这样
{# src/Blogger/BlogBundle/Resources/views/Page/contact.html.twig #}
{% extends 'BloggerBlogBundle::layout.html.twig' %}
{% block title %}Contact{% endblock%}
{% block body %}
<header>
<h1>Contact symblog</h1>
</header>
<p>Want to contact symblog?</p>
<form action="{{ path('BloggerBlogBundle_contact') }}" method="post" {{ form_enctype(form) }} class="blogger">
{{ form_errors(form) }}
{{ form_row(form.name) }}
{{ form_row(form.email) }}
{{ form_row(form.subject) }}
{{ form_row(form.body) }}
{{ form_rest(form) }}
<input type="submit" value="Submit" />
</form>
{% endblock %}
我几乎不建议通过本教程来开始使用symfony2