我必须按升序打印一组四个数字（作为数组）。但我的输出并没有正确输出我需要的东西。继承人我所拥有的：
.data
array: .space 40
prompt: .asciiz "Enter a number: "
spacee: .asciiz " "
output: .asciiz "The numbers ascending: "
.text
main:
li $t1,4 #load 4 into $t1
la $a1,array #load a pointer to array into $a1
loop:
addi $t1,$t1,-1 #subtract 1 from $t1, save to $t1
li $v0,4 #load 4 into $v0 (print string)
la $a0,prompt #load prompt text into $a
syscall #display prompt
li $v0,5 #load 5 into $v0 (read integer)
beq $v0, $zero, quit
syscall #prompt for input
sw $v0,0($a1) #store input int to array
addi $a1,$a1,4 #add 4 to $a1, save to $a1
bnez $t1,loop #if $t1 isn't zero,goto loop
li $t1,9 #if $t1 is zero, load 9 into $t1
li $t2,9 #and load 9 into $t2
la $a1,array #load array pointer into $a1
loop1:
beqz $t2,here #if $t2 is zero, goto here
addi $t2,$t2,-1 #subtract 1 from $t2, save to $t2
lw $t5,0($a1) #load an input int into $t5
lw $t6,4($a1) #load the next one into $t6
addi $a1,$a1,4 #add 4 to $a1, save to $a1
ble $t5,$t6,loop1 #if $t5 <= $t6, goto loop1
sw $t5,0($a1) #else, store $t5 in $a1
sw $t6,-4($a1) #and store $t6 in $a1-4 (swapping them)
bnez $t2,loop1 #if $t2 is not zero, to go loop1
here:
la $a1,array #load array into $a1
addi $t1,$t1,-1 #subtract 1 from $t1, save to $t1
add $t2,$t2,$t1 #add $t2 to $t1, save to $t2
bnez $t1,loop1 #if $t1 isn't zero, goto loop1
li $v0,4 #load 4 into $v0 (print string)
la $a0,output #load 'the numbers are' into $a0
syscall #display message to screen
la $a1,array #load array pointer into $a1
li $t1,4 #load 10 into $t1
loop2:
li $v0,1 #load 1 into $v0 (print int)
lw $a0,0($a1) #load $a1 into $a0
syscall #print first number to screen
li $v0,4 #load 4 into $v1 (print string)
la $a0,spacee #load ' ' into $a0
syscall #print ' ' to screen
addi $a1,$a1,4 #add 4 to $a1, save to $a1
addi $t1,$t1,-1 #subtract 1 from $t1, save to $t1
bnez $t1,loop2 #if $t1 isn't zero, goto loop2
quit:
li $v0,10 #exit
syscall
问题是......它不是打印任何东西，而是＆＃34; 0 0 0 0＆＃34; 有什么帮助吗？