Question

所以，我是Java的新手，但我正在尝试制作一个特定于类的程序，以便我可以在Java中开发游戏。这是我的代码：

import java.util.Scanner;
public class boxtype {
public static void main(String args[]) {
    String[] melee = {"Crowbar", "Bowie Knife", "Butterfly Knife", "Knuckleduster"};
    String[] pistol = {"Colt .22", "Magnum .45", "P250", "9mm Pistol"};
    String[] assault = {"AK47", "M4A1", "M16", "SMG", "Mac10", "Minigun (HGE)"};
    String[] shotgunsniper = {"Shotgun", "Benelli S90", "Sniper Rifle"};
    String[] attachments = {"Laser Sight", "Silencer", "Scope", "Auto-target"};
    Scanner scan = new Scanner(System.in);
    String xy = scan.nextLine();
    if (xy.equals("spyclass")) {
        spyClass();
    }

}
private static void spyClass(String[] assault, String[] attachments, String[] pistol) {
    // TODO Auto-generated method stub
    System.out.println("Spy class: ");
    System.out.println("Primary weapon: " + assault[2] + " + " + attachments[2]);
    System.out.println("Secondary weapon: " + pistol[1] + " + " + attachments[2]);
    System.out.println("");
}

}

基本上会发生什么，Eclipse会返回一个错误，说＆＃34; spyClass不适用＆＃34;。我还在研究如何解决，但是。是的。

Answer 1

在对spyClass的调用中，你没有传递参数

应该是：

if (xy.equals("spyclass")) {
    spyClass(assault, attachments, pistol);
}

Answer 2

你的spyClass方法需要一堆参数，但你不能给它任何参数。该行

    spyClass();

或许应该像

    spyClass(assault, attachments, piston);

Answer 3

spyClass可能不应该是static，当您在main方法中调用它时，您需要将参数传递给它。 spyClass(assault, attachments, pistol);

如何正确使用Java方法？

3 个答案: