Question

我无法弄清楚这段代码有什么问题，它应该从我创建的php页面获取数据。我在Eclipse SDK中使用Eclipse。

    package com.myproject.myproject2;


import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;

import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.ParseException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;

import android.app.Activity;
import android.os.Bundle;
import android.util.Log;
import android.widget.TextView;
public class EntList extends Activity {

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.entlist);

        JSONArray jsonArray = null;

        String jsonString = null;

        StringBuilder stringBuilder = null;

        InputStream inStream = null;

        TextView tv = (TextView) findViewById(R.id.listtitle);



        ArrayList<NameValuePair> nVPArray = new ArrayList<NameValuePair>(); //This is empty because you're asking for data
        try{
            //Connect to your script, and save get an object to read the data (inStream)
             HttpClient client = new DefaultHttpClient();
             HttpPost post = new HttpPost("http://sawtaljabal.com/ar/android_connect/test.php"); // Be sure to replace with your actual script
             post.setEntity(new UrlEncodedFormEntity(nVPArray)); 
             HttpResponse postResponse = client.execute(post); 
             HttpEntity responseEntity = postResponse.getEntity();
             inStream = responseEntity.getContent();
             }catch(Exception e){
                 Log.e("Error connecting", e.getLocalizedMessage());
            }

        try{
            //read the stream to a single JSON string
              BufferedReader reader = new BufferedReader(new InputStreamReader(inStream,"iso-8859-1"), 10); // iso-8859-1 is the character converter
               stringBuilder = new StringBuilder();
               stringBuilder.append(reader.readLine() + "\n");

               String line="0";
               while ((line = reader.readLine()) != null) {
                              stringBuilder.append(line + "\n");
                }
                inStream.close();
                jsonString = stringBuilder.toString();
                }catch(Exception e){
                      Log.e("Error creating JSON string", e.getLocalizedMessage());
                }


        try{ 
              //Turn the JSON string into an array of JSON objects
              jsonArray = new JSONArray(jsonString);
              JSONObject jsonObject = null;
              for(int i=0;i< jsonArray.length();i++){
                     jsonObject = jsonArray.getJSONObject(i);
                     //do something with the object, like String data = jsonObject.getString("KEY");
                     String data = jsonObject.getString("n_t");
                     tv.setText(data);
                 }
              }
              catch(JSONException e){
               e.printStackTrace();
              } catch (ParseException e) {
           e.printStackTrace();
         }

    }
}

我甚至不知道该尝试什么，请帮助我，这是我的第一份申请表。

Answer 1

如果这是你的第一个Android应用程序，你可能想尝试克隆这个项目并在那里学习代码：

https://github.com/jgilfelt/android-jsonarrayadapter?files=1

希望它有所帮助。

Answer 2

您确定，您在回复中获得的字符串是JSON Array。我认为它应该是JSON object，您可以通过JSON Array获得更多// try parse the string to a JSON object try { jObj = new JSONObject(jsonString); } catch (JSONException e) { }。

表示

{{1}}

然后从JSON Object解析JSON数组。

结帐this链接，可能会有所帮助。

也可以在AsynTask或其他线程中进行所有网络调用。

Answer 3

试试我的代码，它是Bettor使用ResponseHandler它会直接将json响应转换为String，你现在将免于输入流，之后你的代码就好了，祝你好运... :)

For efficient use of this code: 请创建一个asy任务类，并将此代码放入doinbackbrd方法

            try {
            ArrayList<NameValuePair> nvp = new ArrayList<NameValuePair>(2);
            nvp.add(new BasicNameValuePair("key1", "value1"));
            nvp.add(new BasicNameValuePair("key2", "value2"));
            HttpClient httpclient = new DefaultHttpClient();
            HttpPost httppost = newHttpPost("http://sawtaljabal.com/ar/android_connect/test.php");
            httppost.setEntity(new UrlEncodedFormEntity(nvp));
            ResponseHandler<String> responseHandler = new BasicResponseHandler();
            String responseBody = httpclient.execute(httppost, responseHandler);
            // Log.i("response", responseBody);
        } catch (Exception e) {
            Log.i("error1", "" + e.toString());
        }

Answer 4

使用php连接Android 首先，您必须调用一个Web服务（可能是返回php的{{1}}页面），对此页面的调用应该在json类中。然后，您需要以正确的方式解析AsynTask。

您可以尝试任何好的教程。试试this

Android连接php Mysql

4 个答案: