Question

嗨，我是视觉工作室的新手，我总是收到这个错误＆＃34;你的SQL语法有错误;查看与SQL＃34;

对应的手册

这是我的代码，请帮助我谢谢

Public Class Form1
    Dim MysqlConn As MySql.Data.MySqlClient.MySqlConnection

    Dim UsersCommand As New MySql.Data.MySqlClient.MySqlCommand

    Dim UsersAdapter As New MySql.Data.MySqlClient.MySqlDataAdapter

    Dim UsersData As New DataTable

    Dim SQL As String
    Private Sub DataGridView1_CellContentClick(ByVal sender As System.Object, ByVal e As System.Windows.Forms.DataGridViewCellEventArgs) Handles DataGridView1.CellContentClick

    End Sub

    Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
        MysqlConn = New MySql.Data.MySqlClient.MySqlConnection()
        ' Define the SQL to prob data from table.
        SQL = "Select  FROM wala"
        'Connection String
        MysqlConn.ConnectionString = "server=localhost;" & "user id=Taena;" & "password=Taena;" & "database=wala"
        Try
            MysqlConn.Open()
            UsersCommand.Connection = MysqlConn
            UsersCommand.CommandText = SQL
            UsersAdapter.SelectCommand = UsersCommand
            UsersAdapter.Fill(UsersData)
            DataGridView1.DataSource = UsersData

        Catch myerror As MySql.Data.MySqlClient.MySqlException
            MessageBox.Show("Cannot connect to database1" & myerror.Message)
        Finally
            MysqlConn.Close()
            MysqlConn.Dispose()

        End Try
    End Sub
End Class

Answer 1

您错过了要从wala tzable中选择的列。 *是所有列。尝试

Select * FROM wala

甚至可以更好地指定您需要的列

select id, other_column from wala

Answer 2

Select  FROM wala

您没有告诉它选择什么 - 尝试

Select * FROM wala

Answer 3

您需要在select query的位置指定列名或*。这一切都很简单。

您的SQL语法中有错误;检查与您的SQL对应的手册

3 个答案: