Question

假设我得到这张表：

MyTable
+----+-------+
| ID | count |
+----+-------+
| a  | 2     |
| b  | 6     |
| c  | 4     |
| d  | 6     |
| e  | 2     |
+----+-------+

现在我想要回来：

Result
+----+-------+
| ID | count |
+----+-------+
| b  | 6     |
| d  | 6     |
+----+-------+

我想要具有最多计数值的ID。因此，如果有多个最大值，我想要它们全部。另外，我不知道是否会有多个值，如果有，那么它将会是多少。

Answer 1

您可以在子查询中获得最大的价值。例如，

SELECT  *
FROM    MyTable
WHERE   count = 
        (
            SELECT  MAX(count) 
            FROM    MyTable
        )

Answer 2

SELECT
  Id, count
FROM MyTable
WHERE count = (SELECT MAX(count) FROM MyTable)

Answer 3

select * from MyTable where count in (select max(count) from MyTable)

Answer 4

select * from mytable 
where 
  count= (select max(count) from mytable )

Answer 5

试试这个

select ID, count from table where count in (
    select distinct count from table order by Value desc limit 1
) order by count desc

您仅请求了第一行，但是根据此查询，如果您想要前三名，您可以轻松地将其更改为limit 3

Answer 6

您可以使用join而不是使用子查询

SELECT *,t.max_count 
FROM Table1 t1
JOIN (SELECT MAX(`count`) max_count FROM Table1 ) t
HAVING t1.`count`=t.max_count

Fiddle Demo

Answer 7

试试这个：

select id, max(count) as max_count 
  from table1 where count=(select max(count) from table1)
group by id