的web.xml:
<servlet>
<servlet-name>SendEmail</servlet-name>
<servlet-class>SendEmail</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>SendEmail</servlet-name>
<url-pattern>/SendEmail</url-pattern>
</servlet-mapping>
SendEmail servlet:
// File Name SendEmail.java
import java.io.*;
import java.util.*;
import javax.servlet.*;
import javax.servlet.http.*;
import javax.mail.*;
import javax.mail.internet.*;
import javax.activation.*;
public class SendEmail extends HttpServlet{
public void doGet(HttpServletRequest request,
HttpServletResponse response)
throws ServletException, IOException
{
// Recipient's email ID needs to be mentioned.
String to = "theimmortalbg@gmail.com";
// Sender's email ID needs to be mentioned
String from = "web@gmail.com";
// Assuming you are sending email from localhost
String host = "localhost";
// Get system properties
Properties properties = System.getProperties();
// Setup mail server
properties.setProperty("mail.smtp.host", host);
// Get the default Session object.
Session session = Session.getDefaultInstance(properties);
// Set response content type
response.setContentType("text/html");
PrintWriter out = response.getWriter();
try{
// Create a default MimeMessage object.
MimeMessage message = new MimeMessage(session);
// Set From: header field of the header.
message.setFrom(new InternetAddress(from));
// Set To: header field of the header.
message.addRecipient(Message.RecipientType.TO,
new InternetAddress(to));
// Set Subject: header field
message.setSubject("This is the Subject Line!");
// Now set the actual message
message.setText("This is actual message");
// Send message
Transport.send(message);
String title = "Send Email";
String res = "Sent message successfully....";
String docType =
"<!doctype html public \"-//w3c//dtd html 4.0 " +
"transitional//en\">\n";
out.println(docType +
"<html>\n" +
"<head><title>" + title + "</title></head>\n" +
"<body bgcolor=\"#f0f0f0\">\n" +
"<h1 align=\"center\">" + title + "</h1>\n" +
"<p align=\"center\">" + res + "</p>\n" +
"</body></html>");
}catch (MessagingException mex) {
mex.printStackTrace();
}
}
}
当我用eclipse ee运行servlet与tomcat服务器tomcat无法启动时。 我认为原因是Mimemessage,但为什么呢?我知道我的问题mb是愚蠢的,但我是Java EE的新手并且无法理解请帮助