我有两种模式,多对一关系:
class Meal extends \Eloquent {
/**
* public Integer $id; - primary key
* public String $name;
*/
protected $fillable = array('id','name');
public function mealProperties()
{
return $this->hasMany('MealProperty');
}
}
class MealProperty extends \Eloquent {
/**
* public Integer $id; - primary key
* public Integer $meal_id;
*/
protected $fillable = array('id','meal_id');
public function meal()
{
return $this->belongsTo('Meal', 'meal_id');
}
}
如果我要求第一餐第一餐属性一切顺利:
$mealProp = Meal::first()->mealProperties->first();
但如果我用这种方式询问具有第一餐特定身份的mealProperty:
$mealProp = Meal::first()->mealProperties->where('id','=','1')->first();
我收到此错误:
Call to undefined method Illuminate\Database\Eloquent\Collection::where()
我谷歌我两个小时做错了什么,但仍然没有。
如果我不能使用哪种方法,有什么方法可以获得特定的膳食属性?
谢谢你的帮助!
答案 0 :(得分:10)
自v5发布以来,where
对象上有一个方法Support\Collection
,因此这个问题/答案变得无关紧要。该方法与filter
完全相同,即。立即返回过滤后的集合:
$mealProp = Meal::first()->mealProperties->where('id','=','1'); // filtered collection
// that said, this piece of code is perfectly valid in L5:
$mealProp = Meal::first()->mealProperties->where('id','=','1')->first();
你必须区分Laravel行为:
(动态属性)Eloquent Collection或Model
$meal->mealProperties
关系对象
$meal->mealProperties()
现在:
// mealProperties is Eloquent Collection and you call first on the Collection here
// so basically it does not affect db query
$mealProp = Meal::first()->mealProperties->first();
// here you try to add WHERE clause while the db query is already called
$mealProp = Meal::first()->mealProperties->where('id','=','1')->first();
// So this is what you want to do:
$mealProp = Meal::first()->mealProperties()->where('id','=','1')->first();
答案 1 :(得分:1)
你可以试试这个:
$mealProop1 = Meal::first()->mealProperties->find(1); // id = 1
或类似的东西:
$mealProops = Meal::first()->mealProperties;
$mealProop5 = $mealProops->find(5); // id = 5
$mealProop7 = $mealProops->find(7); // id = 7
而不是:
$mealProp = Meal::first()->mealProperties->where('id','=','1')->first();
此外,以下应该有效:
$mealProp = Meal::first()->mealProperties->first();