Question

我正在尝试通过对话框菜单从列表视图中删除项目。选择项目后，我会检索项目的名称，并根据项目的名称提供删除该项目的选项。但是当我尝试删除并重新加载listview时（见图）。我在SQL语句中遇到错误。

图片：http://i.imgur.com/zkmadGf.png

这是删除方法：

termList.setOnItemClickListener(new OnItemClickListener() {
    @Override
    public void onItemClick(AdapterView<?> adapter, View view, int position, long id) {
        final String termName = ((TextView) view.findViewById(R.id.tv_termName)).getText().toString();
        builder.show();
        builder.setAdapter(menAdapter, new DialogInterface.OnClickListener() {
            @Override
            public void onClick(DialogInterface dialog, int which) {
                String term = termName;
                switch (which) {
                    case 0:
                        Context c = MainActivity.this;
                        Intent i = new Intent(c, CourseListActivity.class);
                        i.putExtra("termName", term);
                        c.startActivity(i);
                        break;
                    case 1:
                        db.delete("termTable", "name = " + term, null);
                        termListAdapter.notifyDataSetChanged();
                }
            }
        });
    }
});

这是日志文件：

04-08 14:27:00.190: E/AndroidRuntime(26451): FATAL EXCEPTION: main
04-08 14:27:00.190: E/AndroidRuntime(26451): android.database.sqlite.SQLiteException: near "Name": syntax error: , while compiling: DELETE FROM termTable WHERE name = Term Name: hello
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.database.sqlite.SQLiteCompiledSql.native_compile(Native Method)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.database.sqlite.SQLiteCompiledSql.<init>(SQLiteCompiledSql.java:68)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.database.sqlite.SQLiteProgram.compileSql(SQLiteProgram.java:143)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.database.sqlite.SQLiteProgram.compileAndbindAllArgs(SQLiteProgram.java:361)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.database.sqlite.SQLiteStatement.acquireAndLock(SQLiteStatement.java:260)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.database.sqlite.SQLiteStatement.executeUpdateDelete(SQLiteStatement.java:84)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.database.sqlite.SQLiteDatabase.delete(SQLiteDatabase.java:1759)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at com.dagonar.achievegpa.MainActivity$2$1.onClick(MainActivity.java:89)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at com.android.internal.app.AlertController$AlertParams$3.onItemClick(AlertController.java:938)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.widget.AdapterView.performItemClick(AdapterView.java:292)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.widget.AbsListView.performItemClick(AbsListView.java:1485)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.widget.AbsListView$PerformClick.run(AbsListView.java:2941)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.widget.AbsListView$1.run(AbsListView.java:3658)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.os.Handler.handleCallback(Handler.java:605)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.os.Handler.dispatchMessage(Handler.java:92)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.os.Looper.loop(Looper.java:137)
04-08 14:27:00.190: E/AndroidRuntime(26451):    at android.app.ActivityThread.main(ActivityThread.java:4464)

我希望你能帮我找到解决方案。

Answer 1

可能你的目标是执行以下声明：

DELETE FROM termTable WHERE name = 'hello'

而不是：

DELETE FROM termTable WHERE name = Term Name: hello

所以正确的代码是：

String term = termName.split(":")[1].trim();
switch (which) {
    case 0:
        Context c = MainActivity.this;
        Intent i = new Intent(c, CourseListActivity.class);
        i.putExtra("termName", term);
        c.startActivity(i);
        break;
    case 1:
        db.delete("termTable", "name = '" + term + "'", null);
        termListAdapter.notifyDataSetChanged();
}

请将标签和值分成2 TextViews，不要将所有内容放在TextView内。

Answer 2

将术语值视为＆＃34;术语名称：hello＆＃34;，您需要的是什么 db.delete（＆＃34; termTable＆＃34;，＆＃34; name =＆＃34; +＆＃34;＆＃39; + term +＆＃39;＆＃34;，null）;

从SQLite数据库中删除项目并更新ListView

2 个答案: