Question

我有一个填充了MySQL查询结果的表。我需要在表中插入一个额外的列作为PHP函数，它根据查询中字段的值生成一个字符串（我认为这是问题需要解决的方法）。这可能吗？我已经尝试将列设置为变量并在函数中调用该变量（在此代码中未设置为用户定义的函数），但我必须做错了，因为表根本没有填充。

$query1 = "SELECT `rank`.`term`,
                    `rank`.`acadplan`, 
                    `rank`.`projlvl`, `rank`.`gpa`, 
                    (SELECT COUNT(gpa) FROM `rank1` 
                    WHERE `rank1`.`term` = '{$term}'
                        AND `rank1`.`acadplan`='{$acadplan}' 
                        AND `rank1`.`projlvl`='{$projlvl}' 
                        AND `rank1`.`gpa` > `rank`.`gpa`) + 1 AS 'ranking',
                FROM `rank` 
                    WHERE `rank`.`term` ='{$term}'
                        AND `rank`.`acadplan`='{$acadplan}'  
                        AND `rank`.`projlvl`='{$projlvl}' 
                ORDER BY `rank`.`gpa` DESC";


$result = mysqli_query($query1);
    echo "<table>";
        echo "<th>Term</th>";
        echo "<th>Plan</th>";
        echo "<th>Level</th>";
        echo "<th>GPA</th>";
        echo "<th>Rank</th>";
        echo "<th>NEWCOL</th>";
    echo "<col width = '125'>";
    echo "<col width = '125'>";
    echo "<col width = '125'>";
    echo "<col width = '125'>";
    echo "<col width = '125'>";
    echo "<col width = '250'>";


$num_rows = mysqli_num_rows($result);

这是需要执行的功能：

if ($num_rows <=24) {
    switch ($num_rows) {
        case ($rank >=1 and $rank <=3):
            echo "1-3";
            break;
        case ($rank >=4 and $rank <=6):
            echo "4-6";
            break;
        case ($rank >=7 and $rank <=9):
            echo "7-9";
            break;
        case ($rank >=10 and $rank <=12):
            echo "10-12";
            break;
        case ($rank >=13 and $rank <=15):
            echo "13-15";
            break;
        case ($rank >=16 and $rank <=18):
            echo "16-18";
            break;
        case ($rank >=19 and $rank <=21):
            echo "19-21";
            break;
        case ($rank >=22 and $rank <=24):
            echo "22-24";
            break;
        }
    } elseif ($num_rows >=25 and $num_rows <=50) {
        echo "greater than 24";
    } elseif ($num_rows >=51 and $num_rows <=100) {
        echo "greater than 50";
    } elseif ($num_rows >=101 and $num_rows <=150) {
        echo "greater than 100";
    } elseif ($num_rows >=151 and $num_rows <=260) {
        echo "greater than 150";
    }
}

这是表格：

while($row = mysqli_fetch_array($result))
    {
    echo "<tr>";
    echo "<td>" . $row['term'] . "</td>";
    echo "<td>" . $row['acadplan'] . "</td>";
    echo "<td>" . $row['projlvl'] . "</td>";
    echo "<td>" . $row['gpa'] . "</td>"; 
    echo "<td>" . $row['ranking'] . "</td>";
    echo "</tr>";
    }
echo "</table>";

Answer 1

像这样的解决方案怎么样：

 function someFunction($rank, $num_rows) {
     if ($num_rows <=24) {
        switch (true) {
            case ($rank >= 1 AND $rank <=3):
                return "1-3";
            case ($rank <=6):
                return "4-6";
            case ($rank <=9):
                return "7-9";
            case ($rank <=12):
                return "10-12";
            case ($rank <=15):
                return "13-15";
            case ($rank <=18):
                return  "16-18";
            case ($rank <=21):
                return "19-21";
            case ($rank <=24):
                return "22-24";
        }
    } elseif ($num_rows >=25 and $num_rows <=50) {
         return "greater than 24";
    } elseif ($num_rows >=51 and $num_rows <=100) {
        return "greater than 50";
    } elseif ($num_rows >=101 and $num_rows <=150) {
        return "greater than 100";
    } elseif ($num_rows >=151 and $num_rows <=260) {
        return "greater than 150";
    }
    return "";
}

然后是表格：

while($row = mysqli_fetch_array($result))
{
    echo "<tr>";
    echo "<td>" . $row['term'] . "</td>";
    echo "<td>" . $row['acadplan'] . "</td>";
    echo "<td>" . $row['projlvl'] . "</td>";
    echo "<td>" . $row['gpa'] . "</td>"; 
    echo "<td>" . $row['ranking'] . "</td>";
    echo "<td>" . someFunction($row['ranking'], $num_rows) . "</td>";
    echo "</tr>";
}
echo "</table>";

编辑：您可以在HTML标记中使用PHP：

<td><?php echo $row['ranking']; ?></td>

我发现在我的视图中使用PHP值的首选方法。当然，如果可能的话，严格的业务逻辑应该分开，而不是放在HTML标签中。

PHP函数与MySQL查询表

1 个答案: