Question

我正在制作这个新的servlet：

package Servlets;

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

/**
 * Servlet implementation class Hello
 */
public class Hello extends HttpServlet
{
    private static final long   serialVersionUID    = 1L;

    /**
     * @see HttpServlet#HttpServlet()
     */
    public Hello()
    {
        super();
    }

    /**
     * @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
     */
    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
    {
        response.setContentType("text/html");

        PrintWriter out = response.getWriter();
        out.println("It works");
        out.close();
    }

    /**
     * @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
     */
    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
    {
        doGet(request, response);
    }

}

这是我在WEB-INF中的web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
  <display-name>FirstServlet</display-name>
  <welcome-file-list>
    <welcome-file>index.html</welcome-file>
    <welcome-file>index.htm</welcome-file>
    <welcome-file>index.jsp</welcome-file>
    <welcome-file>default.html</welcome-file>
    <welcome-file>default.htm</welcome-file>
    <welcome-file>default.jsp</welcome-file>
  </welcome-file-list>

   <servlet>
      <servlet-name>Hello</servlet-name>
      <servlet-class>Hello</servlet-class>
   </servlet>

   <servlet-mapping>
      <servlet-name>Hello</servlet-name>
      <url-pattern>/hello</url-pattern>
   </servlet-mapping>
</web-app>

我创建动态Web项目时会自动生成display-name和welcome-file-list标记。 servlet和servlet-mapping是由我编写的。当我用appache 7运行项目时，它说HTTP Status 404 - / FirstServlet /。我的错误在哪里？

Answer 1

1）您可能缺少列出的所有欢迎文件。当没有404时，应该发生404。

2）您的servlet映射已损坏。 servlet-class元素需要一个完全限定的类名，它应该是Servlets.Hello，而不仅仅是Hello。正确映射后，/FirstServlet/hello将到达您的servlet，匹配映射的URI，然后按名称查找已注册的servlet，最后到应该执行的完全限定的类。

如何使用eclipse kepler和apache创建和运行servlet 7

1 个答案: