如何在jQuery中返回值？

Question

我想要退回respone。我打电话给我的第一个提醒是undefined（这意味着它没有返回）和第二个提醒true。

 alert(checkDeviceDataNetwork());
 function checkDeviceDataNetwork(){
   var networkResponse;
   bridge_g.callHandler('NetworkReachable',"" , function(response) {
               alert(response);
               networkResponse=response; 
               return networkResponse;
               if(response=="false"){
                    alert("Please check the network");
               }});
 } 

Answer 1

将回调发送到函数

 checkDeviceDataNetwork(function(err, message) {
   // bubble error if present; check console for this one
   if (err) throw err;

   // otherwise alert message
   alert(message);
 });

 function checkDeviceDataNetwork(callback){
   var networkResponse;
   bridge_g.callHandler('NetworkReachable',"" , function(response) {
               callback(null, response);
               networkResponse=response; 
               if(response=="false"){
                    callback(Error("Please check the network"));
               }
               return networkResponse;
       });
 }