Question

我知道这是一个奇怪的问题，但我需要一件事：我收到一个字符串作为http操作的结果。实际上，这个字符串包含一个字符串数组，如下所示：

["Leon","Prova 2","TestData"]

基本上我想将这个字符串转换为ArrayList，因为我需要它用于适配器。这是java代码：

public class Archivio{

    static ArrayList<String> titoli = new ArrayList<String>();
    static ArrayList<String> art = new ArrayList<String>();
    static String response, response2 = null;
    HttpClient httpclient;
     HttpPost httppost,httppost2;
     List<NameValuePair> nameValuePairs,namePairs;
    @SuppressLint({ "NewApi", "NewApi", "NewApi" })
    Archivio() {

        try {

            StrictMode.ThreadPolicy policy = new
                    StrictMode.ThreadPolicy.Builder()
                    .permitAll().build();
                    StrictMode.setThreadPolicy(policy);

                    httpclient=new DefaultHttpClient();
                     httppost= new HttpPost("http://tripleleon.altervista.org/artiview2.php"); 
                     nameValuePairs = new ArrayList<NameValuePair>();
                      httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
                     //Esecuzione richiesta HTTP Post e ricezione risultato operazione
                     //response=httpclient.execute(httppost);
                     ResponseHandler<String> responseHandler = new BasicResponseHandler();
                     response = httpclient.execute(httppost, responseHandler);
                     System.out.println("Response : " + response); 
                     httppost2= new HttpPost("http://tripleleon.altervista.org/artiview3.php"); 
                     namePairs = new ArrayList<NameValuePair>();
                      httppost2.setEntity(new UrlEncodedFormEntity(nameValuePairs));
                     ResponseHandler<String> responseHandler2 = new BasicResponseHandler();
                     response2 = httpclient.execute(httppost2, responseHandler2);
                     System.out.println("Response : " + response2); 

        } catch (MalformedURLException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }

    ArrayList<String> retTitle() {
        return response;
    }


    ArrayList<String> retArt() {
        return response2;   
    }
}

Answer 1

尝试使用以下代码（stringArray包含“数组”的String代码：

ArrayList<String> myList = new ArrayList<String>(Arrays.asList(stringArray.substring(1, stringArray.length() - 1).replaceAll("\"", "").split(",")));

这将删除第一个和最后一个字符（分别为[和]）并按,字符拆分。然后，使用ArrayList方法将其转换为Arrays.asList。

Answer 2

您可以遍历JSONArray并将其添加到ArrayList。

ArrayList<String> list = new ArrayList<String>();
JSONArray jr = new JSONArray("string");
for(int i=0;i<jr.length();i++)
{
   String value =(String) jr.get(i);
   list.add(value); 
}

但是您没有使用Thread或Asynctask从服务器获取json。不要在生产阶段使用StrictMode。

同时检查清单@SuppressLint({ "NewApi", "NewApi", "NewApi" })中的minsdk。你已经压制了lint警告

将字符串转换为ArrayList <string> </string>

2 个答案: