Question

您好我想自动刷新已检查的页面而不刷新其他页面。我有两个弹出的工作正常，我只是希望单选按钮在检查时工作正常。目前它刷新了10秒后未检查的页面，请有人帮帮我。迅速的回应将受到关注。谢谢

<script type="text/JavaScript">
        $(document).ready(function() {

            setTimeout("timerefresh();", 10000);
        });
        function  timerefresh()
        {
            alert(document.getElementById('hdnReload').value + " Before IF");
            if (document.getElementById('hdnReload').value == 'MainPage')
            {
                var SelectedRadioBtn;
                var radioButtons = document.getElementsByName("rdbOptions");
                for (var x = 0; x < radioButtons.length; x++) {
                    if (radioButtons[x].checked) {
                        alert("You checked " + radioButtons[x].id + " which has the value " + radioButtons[x].value);
                        SelectedRadioBtn = radioButtons[x].value;
                        //$('input[value ="lstScheduled"]').prop('checked', true);
                    }
                }
                setTimeout("location.reload(true);", 10000);
                $('input[value ="'+SelectedRadioBtn+'"]').attr('checked', true);
            }
            else
            {
                setTimeout("timeRefresh()",10000);
            }
        }
    </script>

Answer 1

您可以使用setInterval而不是setTimeout，它会减少您的代码。

setInterval(function () { alert(document.getElementById('hdnReload').value + " Before IF"); if (document.getElementById('hdnReload').value == 'MainPage') { var SelectedRadioBtn; var radioButtons = document.getElementsByName("rdbOptions"); for (var x = 0; x < radioButtons.length; x++) { if (radioButtons[x].checked) { alert("You checked " + radioButtons[x].id + " which has the value " radioButtons[x].value); SelectedRadioBtn = radioButtons[x].value; //$('input[value ="lstScheduled"]').prop('checked', true); } } setTimeout("location.reload(true);", 10000); $('input[value ="' + SelectedRadioBtn + '"]').attr('checked', true); } }, 10000)

选中单选按钮时自动重新加载当前页面，有人可以帮我解决

1 个答案: