Question

我有一个时间选择器功能，可以在EditText中设置时间。但它显示的格式不合适。例如，04：07 pm显示为4：7。只要时间上的数字小于10，它就会自动删除0。请帮帮我。我的代码是

        if (v == btnTimePicker1)
               {

                // Process to get Current Time
                final Calendar c = Calendar.getInstance();
                mHour = c.get(Calendar.HOUR_OF_DAY);
                mMinute = c.get(Calendar.MINUTE);

                // Launch Time Picker Dialog
                TimePickerDialog tpd = new TimePickerDialog(this,
                        new TimePickerDialog.OnTimeSetListener() {

                            @Override
                            public void onTimeSet(TimePicker view, int hourOfDay,
                                    int minute) {
                                // Display Selected time in textbox
                                txtTime1.setText(hourOfDay + ":" + minute);
                            }
                        }, mHour, mMinute, false);
                tpd.show();




            }

Answer 1

只需更改一行：

txtTime1.setText(hourOfDay + ":" + minute);

为：

txtTime1.setText(String.format("%02d:%02d", hourOfDay, minute));

一切都会好的。

如果你想要一个12小时制而不是24小时制，那么用这些代替那一行：

int hour = hourOfDay % 12;
if (hour == 0)
    hour = 12;
txtTime1.setText(String.format("%02d:%02d %s", hour, minute, 
                               hourOfDay < 12 ? "am" : "pm"));

或者你可以用以下两行来完成：

int hour = hourOfDay % 12;    
txtTime1.setText(String.format("%02d:%02d %s", hour == 0 ? 12 : hour,
                               minute, hourOfDay < 12 ? "am" : "pm"));

Answer 2

您可以检查小时和分钟是否小于10。如果是这样，你只需添加＆＃34; 0＆＃34;面对那个特定的字符串。只需像这样修改你的代码：

@Override
    public void onTimeSet(TimePicker view, int hourOfDay,
    int minute) {
        // Display Selected time in textbox

        String hourString;
        if (hourOfDay < 10)
            hourString = "0" + hourOfDay;
        else
            hourString = "" +hourOfDay;

        String minuteSting;
        if (minute < 10)
            minuteSting = "0" + minute;
        else
            minuteSting = "" +minute;

        txtTime1.setText(hourString + ":" + minuteSting);
    }

Answer 3

逻辑很简单，我刚刚修改了上面的答案

用

替换我们在editText中设置时间的行

txtTime.setText(pad(hourOfDay) + ":" + pad(minute));

然后为它添加一个函数，即

       public String pad(int input) 
         {

            String str = "";

            if (input > 10) {

                str = Integer.toString(input);
            } else {
                str = "0" + Integer.toString(input);

            }
            return str;
        }

Answer 4

首先需要创建一个检查输入的函数，并根据条件将其转换为String。

public String pad(int input) {
    if (input >= 10) {
        return String.valueOf(input);
    } else {
        return "0" + String.valueOf(input);
    }
}

然后你可以像这样打电话

 txtTime1.setText(pad(hourOfDay) + ":" + pad(minute));

Answer 5

您可以使用以下代码 -

  public void onTimeSet(TimePicker view, int hourOfDay, int minuteOfDay) {
   int hour;
   String minute, amOrPm;
   if (hourOfDay > 12) {
    hour = hourOfDay - 12;
    amOrPm= "PM";
   } else {
    hour = hourOfDay;
    amOrPm = "AM";
   }
   if(minuteOfDay < 10) {
      minute = "0"+minuteOfDay;
   } else {
      minute = "" + minuteOfDay;
   }
   txtTime1.setText(hour + " : " + minute + " " + amOrPm);
  }

Answer 6

SubContent

Answer 7

试试这个

simpleTimePicker1 = (TimePicker) findViewById(R.id.timedawn);
simpleTimePicker1.setIs24HourView(true);
simpleTimePicker1.setOnTimeChangedListener(new TimePicker.OnTimeChangedListener() {
    @Override
    public void onTimeChanged(TimePicker view, int hourOfDay1, int minute1 ) {

        String shour1 = String.valueOf(hourOfDay1);
        String sminute1 = String.valueOf(minute1);


        if ((shour1.length() == 1 ) && (sminute1.length() == 1)) {
            sHour1= "0" + shour1;
            sMinute1= "0" + sminute1;
        }
        else if ((shour1.length() == 2 ) && (sminute1.length() == 1)) {
            sHour1= shour1;
            sMinute1= "0" + sminute1;
        }
        else if ((shour1.length() == 1 ) && (sminute1.length() == 2)) {
            sHour1= "0" + shour1;
            sMinute1= sminute1;
        }
        else{
            sHour1= shour1;
            sMinute1= sminute1;
        }
        String timew = sHour1+":" + sMinute1;
        time3=timew;
    }

});

Answer 8

我参加聚会可能有点晚，但这肯定会对其他人有所帮助。

 private String getTime(int hr, int min) {
    Time tme = new Time(hr, min, 0);//seconds by default set to zero
    Format formatter;
    formatter = new SimpleDateFormat("h:mm a");
    return formatter.format(tme);
}

时间选择器显示时间像4：7而不是04:07

8 个答案: