对于hql中的分区,row_number()的等价物是什么 我在hql中有以下查询:
select s.Companyname, p.Productname, sum(od.Unitprice * od.Quantity - od.Discount) as SalesAmount FROM OrderDetails as od inner join od.Orders as o inner join od.Products as p " +
"inner join p.Suppliers as s" +
" where o.Orderdate between '2010/01/01' and '2014/01/01' GROUP BY s.Companyname,p.Productname"
我希望按s.Companyname
RowNumber <= n
进行分区。
答案 0 :(得分:3)
据我所知,您无法在HQL或JPQL中使用row_number()
。我建议在这种情况下使用native SQL查询:
@PersistenceContext
protected EntityManager entityManager;
...
String sQuery = "SELECT q.* FROM (" +
"SELECT s.company_name, " +
"p.product_name, " +
"sum(od.unit_price * od.quantity - od.discount) as SalesAmount, " +
"row_number() OVER (partition by s.company_name) as rn " +
"FROM OrderDetails od " +
"INNER JOIN Orders o ON o.id = od.order_id " +
"INNER JOIN Products p ON p.id = od.product_id " +
"INNER JOIN Suppliers s ON s.id = p.supplier_id " +
"WHERE o.order_date between '2010/01/01' and '2014/01/01') as q " +
"WHERE rn <= :n";
List<ResultDbo> results = new ArrayList<>();
Query query = entityManager.createNativeQuery(sQuery);
query.setParameter("n", n);
List<Object[]> resultSet = query.getResultList();
for (Object[] resultItem : resultSet) {
ResultDbo result = new ResultDbo();
result.setCompanyName((String) resultItem[0]);
result.setProductName((String) resultItem[1]);
result.setSalesAmount((String) resultItem[2]);
results.add(result);
}
如果您尝试在HQL中使用OVER()
,您几乎肯定会得到一些验证异常,例如java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected token: OVER near line 1, column 42 ...
答案 1 :(得分:1)
分区的行号如下所示:
row_number() over (partition by s.Companyname)
您不能在row_number
子句中使用窗口函数where
,因此您必须使用过滤器的值来执行子查询:
select * from (
-- here is your query
select
...,
row_number() over (partition by s.Companyname) as rowNum
from ...
where ...
) as res
where rowNum <= n