我有以下型号:
class Author(db.Model):
name = db.StringProperty()
class Story(db.Model):
author = db.ReferenceProperty(Author)
某个作者找到所有故事的原始GQL是什么。在常规SQL中,我将使用连接,但我不认为它在GQL中可用。
修改
我正在寻找原始的GQL方式,我知道如何以Pythonic的方式做到这一点。例如(以下可能是完全错误的):
"SELECT * FROM Story WHERE author = :1", "Shakespeare"
我想从GAE管理数据>运行上述内容。数据查看器>查询数据存储区。我想要有人可以从典型的mysql或psql shell运行的原始SQL。
答案 0 :(得分:4)
Edit2:啊,用于数据查看器的raw-GQL ...
这是一种方式:
1)运行此命令并获取ID号:
SELECT * FROM Author where name = 'shakespeare'
2)使用上一个查询中的ID号,运行:
SELECT * FROM Story where author = key('Author', 12345)
编辑:最后,原始GQL:
(最简单的方法:使用隐式反向引用属性名称;格式为“modelname_set”。)
qry = GqlQuery("SELECT * FROM Author WHERE name = :1", "shakespeare")
shakespeare = qry.get()
shakespeare.story_set # this property now contains all Shakespeare's stories
或
qry0 = GqlQuery("SELECT * FROM Author WHERE name = :1", "shakespeare")
shakespeare = qry0.get()
qry1 = GqlQuery("SELECT * FROM Story WHERE author = :1", shakespeare.key())
shakespeare_stories = qry1.fetch(10) # probably good to have some limit here
我更喜欢这种方式:
qry = Author.all()
qry.filter('name = ', 'shakespeare')
shakespeare = qry.get()
shakespeare.story_set # this property now contains all Shakespeare's stories
有时可能需要更多参与方式:
qry0 = Author.all()
qry0.filter('name = ', 'shakespeare')
shakespeare = qry0.get()
qry1 = Story.all()
qry1.filter('author = ', shakespeare.key())
shakespeare_stories = qry1.fetch(10) # probably good to have some limit here