如何使RadioGroup显示2个不同的ListView

时间:2014-03-30 19:22:12

标签: android eclipse listview radio-button radio-group

我要做的是,你有2个RadioButton,当你点击其中一个时,它会显示一个ListView1,当你点击另一个RadioButton时,它会显示一个ListView2

这是我在我的xml文件中得到的:

<RadioGroup
    android:id="@+id/radioGroup1"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:layout_alignParentTop="true"
    android:layout_centerHorizontal="true"
    android:orientation="horizontal" >

    <RadioButton
        android:id="@+id/radio0"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:checked="true"
        android:paddingRight="5dp"
        android:text="Free Apps" />

    <RadioButton
        android:id="@+id/radio1"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:text="Paid Apps" />

</RadioGroup>

<ListView
    android:id="@+id/listView1"
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:layout_alignParentLeft="true"
    android:layout_below="@+id/radioGroup1" >
</ListView>

这就是我的.java中的内容:

private void populateListView() {
    // Create list of items
    String[] items = {"Test", "Test 2", "Test 3"};
    String[] items2 = {"Bla", "Bla bla", "Bla bla bla"};

    // Build Adapter
    ArrayAdapter<String> adapter = new ArrayAdapter<String>(this, R.layout.mainitem, items);
    ArrayAdapter<String> adapter2 = new ArrayAdapter<String>(this, R.layout.mainitem, items2);

    // Configure the list view
    ListView list = (ListView) findViewById(R.id.listView1);
    list.setAdapter(adapter);

}

public void onCheckedChanged(RadioGroup group, int checkedId) {
    if(checkedId == R.id.radio0){
         // Show items
    }
    if(checkedId == R.id.radio1){
        // Show items2
    }
}

public void onClick(View v) {
    RadioGroup.clearCheck();
}

如果您还需要别的东西,请告诉我。谢谢!

2 个答案:

答案 0 :(得分:0)

您只需要将populateListView方法中的内容添加到侦听器:

public void onCheckedChanged(RadioGroup group, int checkedId) {
    if(checkedId == R.id.radio0){

        ArrayAdapter<String> adapter = new ArrayAdapter<String>(this, R.layout.mainitem, items);
        ListView list = (ListView) findViewById(R.id.listView1);
        list.setAdapter(adapter);

    } else if(checkedId == R.id.radio1){

        ArrayAdapter<String> adapter = new ArrayAdapter<String>(this, R.layout.mainitem, items2);
        ListView list = (ListView) findViewById(R.id.listView1);
        list.setAdapter(adapter);

    }
}

如果要在清除RadioGroup选项时隐藏或清除列表,只需要在返回-1时添加额外的if,并对列表视图进行更改。来自android参考:"When the selection is cleared, checkedId is -1."

if (checkedId == -1) { ... }

答案 1 :(得分:0)

无需一次又一次地创建新的listview和适配器实例。每次更新数组列表时,您的列表都需要更新。

String[] items = {"Test", "Test 2", "Test 3"};
        String[] items2 = {"Bla", "Bla bla", "Bla bla bla"};
    List<String> arrayList1 = new ArrayList( Arrays.asList(items));
    ArrayAdapter<String> adapter1 = new ArrayAdapter<String>(this,android.R.layout.simple_list_item_1, arrayList1);
ListView list = (ListView) findViewById(R.id.listView1);
list.setAdapter(adapter);


public void onCheckedChanged(RadioGroup group, int checkedId) {

   if(checkedId == R.id.radio0){
         arrayList1.clear();
         arrayList1.addAll(Arrays.asList(items));
    } else if(checkedId == R.id.radio1){
          arrayList1.clear();
         arrayList1.addAll(Arrays.asList(items2));
    }
if(adapter != null){
adapter.notifyDataChange();

}

}