Question

我想根据运算符显示不同的行。像

<code>Sample</code>

$query = oci_parse($con, "SELECT POST.*, USER_LOGIN.*, STATION.*, ROLE.* 
                          FROM USER_LOGIN 
                          INNER JOIN STATION ON USER_LOGIN.S_ID = STATION.S_ID
                          INNER JOIN POST ON USER_LOGIN.USER_ID = POST.USER_ID
                          INNER JOIN ROLE ON USER_LOGIN.ROLE_ID = ROLE.ROLE_ID
                          WHERE ROLE_NAME = 'Operator' ");

任何帮助都将不胜感激。

现在我收到以下错误。我不知道它有什么不对。

Error: ORA-00936: missing expression

$query = oci_parse($con,"SELECT * FROM 

        (SELECT POST.*, USER_LOGIN.*, STATION.*, ROLE.*, IR.*,
        row_number() over(PARTITION BY ROLE_NAME ORDER BY ROLE_NAME) AS seqnum

        FROM USER_LOGIN

        INNER JOIN
        STATION
        ON USER_LOGIN.PS_ID = STATION.PS_ID

        INNER JOIN
        POST
        ON USER_LOGIN.USER_ID = POST.USER_ID

        INNER JOIN
        ROLE
        ON USER_LOGIN.ROLE_ID = ROLE.ROLE_ID

        INNER JOIN
        IR
        ON USER_LOGIN.USER_ID = IR.USER_ID

        WHERE ROLE_NAME = 'Operator') AS t

        WHERE t.seqnum = 1");

Answer 1

我的猜测是您要指定特定列并使用distinct（或group by）：

SELECT DISTINCT operator, cnic, station 
FROM USER_LOGIN INNER JOIN
     STATION
     ON USER_LOGIN.S_ID = STATION.S_ID INNER JOIN
     POST
     ON USER_LOGIN.USER_ID = POST.USER_ID INNER JOIN
     ROLE
     ON USER_LOGIN.ROLE_ID = ROLE.ROLE_ID
WHERE ROLE_NAME = 'Operator';

编辑：

如果你想要一个任意行，那么就这样做：

SELECT *
FROM (SELECT POST.*, USER_LOGIN.*, STATION.*, ROLE.*,
             row_number() over (partition by operator, cnic, station order by operator) as seqnum
      FROM USER_LOGIN INNER JOIN
           STATION
           ON USER_LOGIN.S_ID = STATION.S_ID INNER JOIN
           POST
           ON USER_LOGIN.USER_ID = POST.USER_ID INNER JOIN
           ROLE
           ON USER_LOGIN.ROLE_ID = ROLE.ROLE_ID
      WHERE ROLE_NAME = 'Operator'
     ) t
WHERE seqnum = 1;

row_number()函数枚举组中的行。每个组从1开始。分组由partition by定义，因此具有相同值operator，cnic和station的行将在分组中。 order by指定组内数字的顺序。这是对组使用常量，因此它是任意的。最后一步是where seqnum = 1，它从每个分组中选择一行。

Answer 2

来自： http://docs.oracle.com/cd/B28359_01/server.111/b28286/statements_10002.htm#SQLRF55166

如果希望数据库仅返回所选的每组重复行的一个副本，请指定DISTINCT或UNIQUE。

只需更新代码：

$query = oci_parse($con, "SELECT DISTINCT  POST.*, USER_LOGIN.*, STATION.*, ROLE.* 
    FROM USER_LOGIN 
    INNER JOIN STATION ON USER_LOGIN.S_ID = STATION.S_ID
    INNER JOIN POST ON USER_LOGIN.USER_ID = POST.USER_ID
    INNER JOIN ROLE ON USER_LOGIN.ROLE_ID = ROLE.ROLE_ID
    WHERE ROLE_NAME = 'Operator' ");

不同的行来自列。神谕

2 个答案: