Question

我正在尝试学习JINI库，并找到了简单程序的例子。程序在这里：

package book.basic;
import net.jini.core.discovery.LookupLocator;
import net.jini.core.lookup.ServiceRegistrar;
import java.rmi.RMISecurityManager;
import java.rmi.RemoteException;

/**
 * UnicastRegistrar.java
 */
public class UnicastRegister {
    static public void main(String argv[]) throws RemoteException {
        new UnicastRegister();
    }
    public UnicastRegister() throws RemoteException {
        LookupLocator lookup = null;
        ServiceRegistrar registrar = null;
        System.setSecurityManager(new RMISecurityManager());
        try {
            lookup = new LookupLocator("jini://localhost");
        } catch(java.net.MalformedURLException e) {
            System.err.println("Lookup failed: " + e.toString());
            System.exit(1);
        }
        try {
            registrar = lookup.getRegistrar();
        } catch (java.io.IOException e) {
            System.err.println("Registrar search failed: " + e.toString());
            System.exit(1);
        } catch (java.lang.ClassNotFoundException e) {
            System.err.println("Registrar search failed: " + e.toString());
            System.exit(1);
        }

        System.out.println("Registrar found");
// the code takes separate routes from here for client or service
    }
} // UnicastRegister

如果我运行此应用程序，则抛出异常：

线程中的异常＆＃34; main＆＃34; java.security.AccessControlException：访问被拒绝（＆＃34; java.net.SocketPermission＆＃34;＆＃34; 127.0.0.1：4160＆＃34; ＆＃34;连接，解决＆＃34;）at java.security.AccessControlContext.checkPermission（AccessControlContext.java:372）在 java.security.AccessController.checkPermission（AccessController.java:559）在 java.lang.SecurityManager.checkPermission（SecurityManager.java:549）在java.lang.SecurityManager.checkConnect（SecurityManager.java:1051）在java.net.Socket.connect（Socket.java:574）at java.net.Socket.connect（Socket.java:528）at java.net.Socket。（Socket.java:425）at java.net.Socket。（Socket.java:241）at net.jini.core.discovery.LookupLocator.getRegistrar（LookupLocator.java:328）在 net.jini.core.discovery.LookupLocator.getRegistrar（LookupLocator.java:286）在book.basic.UnicastRegister。（UnicastRegister.java:26）at book.basic.UnicastRegister.main（UnicastRegister.java:12）at sun.reflect.NativeMethodAccessorImpl.invoke0（Native Method）at sun.reflect.NativeMethodAccessorImpl.invoke（NativeMethodAccessorImpl.java:57）在 sun.reflect.DelegatingMethodAccessorImpl.invoke（DelegatingMethodAccessorImpl.java:43）在java.lang.reflect.Method.invoke（Method.java:606）at com.intellij.rt.execution.application.AppMain.main（AppMain.java:120）

我创建了策略文件＆＃34; policy.all＆＃34;并把它放在主目录中：

enter image description here

此文件包含文字：

grant {
    permission java.security.AllPermission;
};

接下来，我在命令行中将此文件作为参数传递： -Djava.security.manager -Djava.security.policy = / policy.all，更像是-Djava.security.manager -Djava.security.policy =。/ policy.all 我在想法中这样做了： enter image description here

我得到下一个编译错误： enter image description here

如果我想直接设置策略文件：

System.setProperty("java.security.policy","file:/policy.all");
System.setSecurityManager(new RMISecurityManager());

它没有产生任何结果，我再次得到java.security.AccessControlException。

在Java中更改系统属性

0 个答案: