Question

由于某些原因，当我将数组传递给方法时，平均值被填充错误，我获得了非常低的百分比。几乎可以看出，由于Array shotsMade只记录制作镜头的整数，而不是未命中，因此不计算正确的基础。

import java.util.*;

public class Test {
public static void main(String[] args) {
    int myGameCounter = 1;  
    int shotCount = 0;
    int shotCount1 = 0;
    int [] shotsMade = new int [5];
    int sum = 0;

    System.out.print("Enter Player's Free Throw Percentage: ");
    Scanner input = new Scanner(System.in);
    int percent = input.nextInt();


    //Game #1
    System.out.println("Game " + myGameCounter + ":");
    Random r = new Random();
    myGameCounter++;
    shotCount = 0;
    for (int i = 0; i < 10; ++i){
        boolean in = tryFreeThrow(percent);
        if (in) {
        shotCount++;
        System.out.print("In" + " ");
        }
        else {
        System.out.print("Out" + " ");
        }
    }

    System.out.println("");
    System.out.println("Free throws made: " + shotCount + " out of 10");
    shotsMade[0]= shotCount;

        //Game #2
    System.out.println("");
    System.out.println("Game" + myGameCounter + ":");
    myGameCounter++;
    shotCount1 = 0;
    for (int i = 0; i < 10; ++i){
        boolean in = tryFreeThrow(percent);
        if (in) {
        shotCount1++;
        System.out.print("In" + " ");
        }
        else {
        System.out.print("Out" + " ");
        }   
    }
    System.out.println("");
    System.out.println("Free throws made: " + shotCount1 + " out of 10");
    shotsMade[1]= shotCount1;

    System.out.println("");
    System.out.println("Summary:");



    System.out.println("Best game: " + max(shotsMade)); 
    System.out.println("Total Free Throws Made: " + sum(shotsMade) + " " + "out of 20");
    System.out.println("Average Free Throw Percentage: " + average(shotsMade) +"%");

} //主

public static boolean tryFreeThrow(int percent) {
    Random r = new Random();
    int number = r.nextInt(100);
    if (number > percent){ 
     return false;
    }
    return true;
}

public static float average(int nums[]) {
    int total = 0;
    for (int i=0; i<nums.length; i++) {
        total = total + nums[i];
    }
    float f = (total / nums.length);
    return (float)total /(float)nums.length;
}

public static int sum(int nums[]) {
    int sum = 0;
    for (int i=0; i<nums.length; ++i) {
        sum += nums[i];
    }
    return (int)sum;
}

public static int max(int nums[]) {
    int max=nums[0];
    for (int i=1; i<nums.length; i++) {
        if (nums[i] > max) 
            max = nums[i];
    }
    return max;
}

} // class

Answer 1

旧问题，您使用整数算术total / nums.length并返回int值。您稍后将其分配给float，但该值已被截断。

在分部之前，只需将其中一个值更改为float ，例如。 ((float) total) / num

Answer 2

您正在计算5个数字的平均值，但您只设置了2个。因此，如果您的阵列中的所有镜头都显示如下：10, 10, 0, 0, 0，平均值将为4。

Answer 3

其中，你的表达

float f = (total / nums.length);

会产生不准确的结果。

total和nums.length都是整数，整数之间的任何操作都会产生整数。

示例：如果total = 10且nums.length = 3，则您希望结果为3.333 ...但实际上结果只是3.只有在那之后才将其转换为浮点数，结果为3.0

要获得所需的结果，您需要在分割之前将两个整数转换为浮点数：

float f = (float) total / (float) nums.length;

通过平均方法传递数组，导致百分比低

3 个答案: