我正在开发一个计步器应用程序,如下所示
到目前为止,我找到了一些解决方案,如下所示:
private void GetDistance(GeoPoint src, GeoPoint dest) {
StringBuilder urlString = new StringBuilder();
urlString.append("http://maps.googleapis.com/maps/api/directions/json?");
urlString.append("origin=");//from
urlString.append( Double.toString((double)src.getLatitudeE6() / 1E6));
urlString.append(",");
urlString.append( Double.toString((double)src.getLongitudeE6() / 1E6));
urlString.append("&destination=");//to
urlString.append( Double.toString((double)dest.getLatitudeE6() / 1E6));
urlString.append(",");
urlString.append( Double.toString((double)dest.getLongitudeE6() / 1E6));
urlString.append("&mode=walking&sensor=true");
Log.d("xxx","URL="+urlString.toString());
// get the JSON And parse it to get the directions data.
HttpURLConnection urlConnection= null;
URL url = null;
url = new URL(urlString.toString());
urlConnection=(HttpURLConnection)url.openConnection();
urlConnection.setRequestMethod("GET");
urlConnection.setDoOutput(true);
urlConnection.setDoInput(true);
urlConnection.connect();
InputStream inStream = urlConnection.getInputStream();
BufferedReader bReader = new BufferedReader(new InputStreamReader(inStream));
String temp, response = "";
while((temp = bReader.readLine()) != null){
//Parse data
response += temp;
}
//Close the reader, stream & connection
bReader.close();
inStream.close();
urlConnection.disconnect();
//Sortout JSONresponse
JSONObject object = (JSONObject) new JSONTokener(response).nextValue();
JSONArray array = object.getJSONArray("routes");
//Log.d("JSON","array: "+array.toString());
//Routes is a combination of objects and arrays
JSONObject routes = array.getJSONObject(0);
//Log.d("JSON","routes: "+routes.toString());
String summary = routes.getString("summary");
//Log.d("JSON","summary: "+summary);
JSONArray legs = routes.getJSONArray("legs");
//Log.d("JSON","legs: "+legs.toString());
JSONObject steps = legs.getJSONObject(0);
//Log.d("JSON","steps: "+steps.toString());
JSONObject distance = steps.getJSONObject("distance");
//Log.d("JSON","distance: "+distance.toString());
String sDistance = distance.getString("text");
int iDistance = distance.getInt("value");
}
我决定用GPS方式实施。 但是,实现这个的“常用方法”是什么?它只是在30秒内获得gps lat,lan,然后计算差异? 例如获取GPS数据之间的间隔有多长。
感谢您的帮助
答案 0 :(得分:2)
执行此功能
getDistanceFromLatLonInKm(lat1,lon1,lat2,lon2) {
var R = 6371; // Radius of the earth in km
var dLat = deg2rad(lat2-lat1); // deg2rad below
var dLon = deg2rad(lon2-lon1);
var a = Math.sin(dLat/2) * Math.sin(dLat/2) +
Math.cos(deg2rad(lat1)) * Math.cos(deg2rad(lat2)) *
Math.sin(dLon/2) * Math.sin(dLon/2);
var c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1-a));
var d = R * c; // Distance in km
return d;
}
function deg2rad(deg) {
return deg * (Math.PI/180)
}
答案 1 :(得分:2)
您可以使用方法计算距离,而不是调用google api。
public double getDistance(double lat1, double lon1, double lat2, double lon2) {
double latA = Math.toRadians(lat1);
double lonA = Math.toRadians(lon1);
double latB = Math.toRadians(lat2);
double lonB = Math.toRadians(lon2);
double cosAng = (Math.cos(latA) * Math.cos(latB) * Math.cos(lonB-lonA)) +
(Math.sin(latA) * Math.sin(latB));
double ang = Math.acos(cosAng);
double dist = ang *6371;
return dist;
}
这将减少一个API调用并快速找到两个位置之间的距离。