Question

这是我的挑战：

我想用来自$ _POST数组的输入更新MySQL表。

这是怎么做到的？（花几个小时寻找解决方案）。

在我的“table.php”中，我从MySQL获取数据并将其放在输入表单中。

在我的“updatesfields.php”中，我无法弄清楚如何更新MySQL中的字段。（我可能会离开，但那不是新闻）

Table.php：

<form method="POST" action="updatefields.php" enctype="multipart/form-data" >
<table border="1"><tr>
<td>ID</td>
<td>Text</td>
</tr>

<?php
$host = "xxx";
$username1 = "xxx";
$password1 = "xxx";
$db_name = "xxx";
$tbl_name = "xxx";

$conn = new PDO("mysql:host=$host;dbname=$db_name",$username1,$password1);
$sql = "SELECT * FROM $tbl_name ORDER BY bilag ASC";
$q = $conn->prepare($sql);
$q->execute(array($title));
$q->setFetchMode(PDO::FETCH_BOTH);

// fetch
while($data = $q->fetch()){

echo "<tr><td>";
// --------------------- ID -----------------------------
$id = $data[0];
if ($id != 0)
{ echo "<center><input type='text' style='font-weight:bold;' value='$id' name='id[]' size='10'>";}
else { echo "<center><input type='text' style='font-weight:bold;' value='' name='id[]' size='10'>"; }
echo "</td>";
// --------------------- ID -----------------------------


echo "<td>";
// --------------------- Text -----------------------------
$text = $data[3];
if ($text != null)
{ echo "<center><input type='text' style='font-weight:bold;' value='$text' name='text[]' size='10'>";}
else { echo "<center><input type='text' style='font-weight:bold;' value='' name='text[]' size='10'>"; }
// --------------------- Text -----------------------------
echo "</td></tr>";
}

?>
</table>
<br>
<input type="submit" value="Update">
</form>

updatefields.php：

<?php

$host = "xxx";
$username1 = "xxx";
$password1 = "xxx";
$db_name = "xxx";
$tbl_name = "xxx";

foreach ($_POST as $number => $text)
{

$conn = new PDO("mysql:host=$host;dbname=$db_name",$username1,$password1);
$sql = "UPDATE $tbl_name SET text=? WHERE id=?]";
$q = $conn->prepare($sql);
$q->execute(array($indsæt,$id)); 

}
?>

Answer 1

首先，在HTML中，我们需要更改它：

<input type="submit" value="Update">

对此。名称是重要的属性，因为它们成为$ _POST数组中的键。

<input type="submit" name="submit" value="Update">

然后，在updatefields.php中：

if (isset($_POST['submit'])){

    //how many ids came through in the $_POST array?
    $id_count = count($_POST['id']);

    //connect only once, before the loop
    $conn = new PDO("mysql:host=$host;dbname=$db_name",$username1,$password1);

    //this runs once for each id we have
    for ($i=0; $i<$id_count; $i++){
        $sql = "UPDATE $tbl_name SET text=? WHERE id=?";
        $q = $conn->prepare($sql);
        $q->bindParam(1, $_POST['text'][$i]);
        $q->bindParam(2, $_POST['id'][$i]);
        $q->execute(); 
        if ($q) {//execute() returns TRUE on success
            //insert success
        } else {
            //insert failed
        }
    }//for loop

} else {//submission did not come from form
     echo "There was a problem processing this request. <a href="Table.php">Please click here to try again.</a>";
}

您可以在the PHP documentation中阅读有关绑定参数的更多信息。

php $ _POST数组并更新MySQL

1 个答案: