Question

继续我之前的2个帖子＆＃39; PHP and MYSQL database connection and table creation only once＆＃39;和＆＃39; Undefined variable in php registration from＆＃39;，在我使用下面的代码将POSTED数据插入我的数据库之前，我没有任何错误。由于我是MYSQLI的新手，我无法理解我的错误并对其进行调试。 PLZ帮助..

//code for input field validation

if (!empty($error)) //send to Database if there's no error '
    {
    $query = $mysqli->prepare("INSERT INTO users ( Name, Username, Password, Email) VALUES (?, ?, ?, ?, ?)");
    $query ->bind_param('sssdi',$fullname, $username, $password2, $email);
    $stmt->execute();
    $newId = $stmt->insert_id;
    $stmt->close();
    //$mysqli->query($query);
    $result = @mysqli_query($query);
    if (!$result) {
    $error['ack'] = 'Failed to Register Your Account...!';
    } else {
    $error['ack2'] = 'Account Registered Successfully...!';
    }
    //$mysqli->close();//Close the DB Connection

我的REGISTRATION.PHP表单位于＆{39; Undefined variable in php registration from＆＃39;链接。

这是我的完整代码会员ID））; ＆＃34 ;; mysql_select_db（＆＃39; USERS＆＃39）; $ retval = mysql_query（$ sql，$ connect）; if（！$ retval）{ 死（＆＃39;不能创建表\ n：＆＃39; .mysql_error（））; } ; mysql_close（$连接）; // DB_connection的结尾

$fullname = "";
$username = ""; 
$password = "";
$password2 = "";
$email = "";

if (isset($_POST['submit'])) {
session_start();
$error = array(); //Declare an array to store error messages  

//validation for fullname
if (!empty($_POST['fullname'])) {
    $fullname = mysql_real_escape_string(trim($_POST['fullname']));
} else {
    $error['fullname'] = 'Enter Fullname...';
}

//validation for username
if (!empty($_POST['username'])){
    $username = mysql_real_escape_string(trim($_POST['username']));
} else {
    $error['username'] = 'Enter Username...';
}

//Validation for password and confirm password
if (!empty($_POST['password'])) {
    if ($_POST['password'] != $_POST['password2']) {
        $error['password2'] = 'Passwords do not match...';
    } else {
        $password2 = mysql_real_escape_string($_POST['password']);
    }
    } else {
        $error['password'] = 'Enter Password...';
}

//validation for e-mail
if (!empty($_POST['email'])) {
    $email = mysql_real_escape_string($_POST['email']);
} else {
    $error['email'] = 'Enter your Email...';
} 

if (!empty($error)) //send to Database if there's no error '
{
$query = $mysqli->prepare("INSERT INTO users ( Name, Username, Password, Email) VALUES        (?, ?, ?, ?, ?)");
$query ->bind_param('sssdi',$fullname, $username, $password2, $email);
$stmt->execute();
$newId = $stmt->insert_id;
$stmt->close();
//$mysqli->query($query);
$result = @mysqli_query($query);
if (!$result) {
$error['ack'] = 'Failed to Register Your Account...!';
} else {
$error['ack2'] = 'Account Registered Successfully...!';
}


}//end of main if
?>
<html>
<form action="register.php" method="post" id="user_registration">
<p id="head">Create Account</p>

<input type="text" id="fullname" name="fullname"/>
**<span class="error" id="fullname"><?php echo $error_name; ?></span>**

<input type="text" id="username" name="username"/>
<span id="availability_status"></span>
**<span class="error" id="username"><?php echo $error_username; ?></span>**

<input type="password" id="password" name="password"/> 
**<span class="error" id="password"><?php echo $error_password; ?></span>**

<input type="password" id="password2" name="password2"/>
**<span class="error" id="divCheckPasswordMatch"><?php echo $error_password2;?></span>**

<input type="email" id="email" name="email"/>
**<span class="error" id="email"><?php echo $error_email; ?></span>**

<p class="submit">
<button type="submit"id="submit" name="submit" value="Register”>Register</button>
</p>

Answer 1

您的查询的问题是值不匹配。如果你看它，你只插入4个值，但你有5个？ 5个值。当你绑定参数“sssdi”代表5时你重复那个错误。所以要么你忘了把一个变量放进去或只是删除额外的它应该没问题。据我所知，所有4个变量应该是字符串，因此将其更改为下面的查询应该有效。

$query = $mysqli->prepare("INSERT INTO users ( Name, Username, Password, Email) VALUES (?, ?, ?, ?)");
        $query ->bind_param('ssss',$fullname, $username, $password2, $email);
        $stmt->execute();

Answer 2

更改您的代码

$query = $mysqli->prepare("INSERT INTO users (Name, Username, Password, Email) VALUES (?, ?, ?, ?)");
 $query->bind_param("ssss", $fullname, $username, $password2, $email);
 $query->execute();

还要仔细检查您的字段名称是否带有第一个大写字母，如果是，则根据您的表格更改字段名称。

PHP MySQLi INSERT查询不起作用

2 个答案: