我有小问题,所以我需要一些帮助。也许它很容易,但我只需要推动......所以我正在使用一个控制器
public function edit($id = null) {
if (!$this->TypologyPicture->exists($id)) {
throw new NotFoundException(__('Invalid typology picture'));
}
if ($this->request->is(array('post', 'put'))) {
if(empty($this->data['TypologyPicture']['pic_path']['name'])){
unset($this->request->data['TypologyPicture']['pic_path']);
}
if ($this->TypologyPicture->save($this->request->data)) {
$this->Session->setFlash(__('The typology picture has been saved.'));
return $this->redirect(array('action' => 'index'));
} else {
$this->Session->setFlash(__('The typology picture could not be saved. Please, try again.'));
}
} else {
$options = array('conditions' => array('TypologyPicture.' . $this->TypologyPicture->primaryKey => $id));
$this->request->data = $this->TypologyPicture->find('first', $options);
//$options1 = array('conditions' => array('Typology.id' => $id));
$opt = array('conditions' => array('Typology.id' => $this->request->data['TypologyPicture']['typology_id']));
$this->request->data = $this->Typology->find('first', $opt);
}
if ( AuthComponent::user('role')==='admin' ||AuthComponent::user('role')==='superadmin' ){ //if the user is admin or superadmin, show all on dropdown
$items = $this->Typology->TypologyItem->find('list');
} else {// else if the user is author, show only item created by him.
$items = $this->Typology->TypologyItem->find('list', array('conditions' => array('TypologyItem.user_id' => AuthComponent::user('id'))));
}
$typologyCategories = $this->Typology->TypologyCategory->find('list');
$typologyConditions = $this->Typology->TypologyCondition->find('list');
$users = $this->Typology->TypologyUser->find('list');
$this->set(compact('items', 'typologyCategories', 'typologyConditions', 'users'));
if ( AuthComponent::user('role')==='admin' ||AuthComponent::user('role')==='superadmin' ){
$typologies = $this->TypologyPicture->ItemTypologyPicture->find('list');
} else {
$typologies = $this->TypologyPicture->ItemTypologyPicture->find('list', array('conditions' => array('ItemTypologyPicture.user_id' => AuthComponent::user('id'))));
}
$this->set(compact('typologies'));
}
因此,您从联系人控制器中看到我想要访问我要编辑的联系人及其存储在 contact_picture 表中的图片。联系人本身就像一个图标或一个头像,并在联系人图片存储在画廊。所以这里的问题是我得到了它应该的所有数据,但是联系人的图像(化身或图标)会显示出来,路径被正确地重新检索但它只是显示图像。
所以我要问的是,如果有另一种方式或简单的方法,甚至更好的方式来做到这一点,我真的会适应它......真的。
提前致谢!
编辑:查看部分:
<?php echo $this->Form->create('TypologyPicture', array('type'=>'file')); ?>
<legend><?php echo __('Edit Typology Picture'); ?></legend>
<?php
$dir = "/img/uploads/typology/images/";
echo $this->Form->input('id'); ?>
<?php echo $this->Form->input('Typology.item_id',array('empty'=>true)); ?>
<?php echo $this->Form->input('Typology.title'); ?>
<?php echo $this->Form->input('Typology.description');?>
<?php echo $this->Form->input('Typology.thumbnail',array('type'=>'file')); ?>
<?php echo $this->Form->input('Typology.typology_category_id',array('empty'=>true)); ?>
<?php echo $this->Form->input('Typology.typology_condition_id',array('empty'=>true)); ?>
<?php echo $this->Form->input('Typology.price',array('placeholder'=>'Price')); ?>
<!-- Here is the second part of the update -->
<?php echo $this->Form->input('pic_path', array('label'=>'Picture','type'=>'file'));
echo $this->Form->input('hiddenimage', array('type'=>'hidden','value'=> $this->Form->value('pic_path') ));
$Image = $this->Form->value( 'pic_path');
if(empty($Image) || $Image==NULL)
{$Image = "/img/uploads/noimg.jpg";}
else {$Image = $dir . $Image; }
echo $this->Html->image($Image,array('align'=>'absbottom','style'=>'max-height:100px'));
?>
<?php echo $this->Form->end(__('Submit')); ?>
因此,当我对图像进行回声时,它会正确显示...如果我像普通编辑一样删除类型模型部分,它会显示正常......
答案 0 :(得分:0)
尝试从$ dir和$ Image中删除img部分;
$dir = "/img/uploads/typology/images/";
应该是
$dir = "uploads/typology/images/";
和
{$Image = "/img/uploads/noimg.jpg";}
应该是
{$Image = "uploads/noimg.jpg";}