Question

我想上传多个图片并将图片名称保存到数据库表中。表格中有两个属性 - id和image_name。在表单中，我使用CMultifileupload小部件上传图像数量。当我提交表格时，没有任何效果。然后我尝试回应if (isset($_POST['ImageTemp'])) {下面的某些东西，但没有效果。所以我暂时看看输出是否有多个图像上传。但是，我写道：

形式：

<div class="form form-custom">

<?php $form=$this->beginWidget('CActiveForm', array(
'id'=>'image-temp-form',
'enableAjaxValidation'=>false,
'htmlOptions'=>array('enctype'=>'multipart/form-data' ),
)); ?>

<p class="note">Fields with <span class="required">*</span> are required.</p>

<?php echo $form->errorSummary($model); ?>

<div class="row">
    <?php echo $form->labelEx($model,'image_name'); ?>
    <?php
    $this->widget('CMultiFileUpload', array(
        'model'=>$model,
        'attribute'=>'image_name',
        //'name' => 'files',
        'accept'=>'jpg|gif|png',
        'denied'=>'File is not allowed',
        'max'=>3, // max 10 files
    ));
    ?>
    <?php echo $form->error($model,'image_name'); ?>
</div>



<div class="row buttons">
    <?php echo CHtml::submitButton($model->isNewRecord ? 'Create' : 'Save'); ?>
</div>

<?php $this->endWidget(); ?>

</div><!-- form -->

控制器中的

：

public function actionCreate()
{

    $model=new ImageTemp;

    $type = isset($_GET['type']) ? $_GET['type'] : 'post';

    if (isset($_POST['ImageTemp'])) {

        echo "something but no output";

        $model->attributes = $_POST['ImageTemp'];
        $photos = CUploadedFile::getInstancesByName('image_name');

        // proceed if the images have been set
        if (isset($photos) && count($photos) > 0) {

            // go through each uploaded image
            foreach ($photos as $image => $pic) {
                echo $pic->name.'<br />';
                if ($pic->saveAs(Yii::getPathOfAlias('webroot').'/images/project'.$pic->name)) {
                    // add it to the main model now
                    $model->image_name = $pic->name; //it might be $img_add->name for you, filename is just what I chose to call it in my model
                    $model->save(); // DONE
                }
                else{
                    echo 'Cannot upload!';
                }
            }
        }

    }

    $this->render('create',array(
        'model'=>$model,
    ));
}

在模型中，我写了规则：

public function rules()
{

    return array(
        array('image_name', 'file','types'=>'jpg, gif, png', 'allowEmpty'=>true, 'on'=>'update'),
        // The following rule is used by search().
        // @todo Please remove those attributes that should not be searched.
        array('id, image_name', 'safe', 'on'=>'search'),
    );
}

我正在尝试基于this，但不明白我做错了什么。

Answer 1

$_FILES['ImageTemp']是你的朋友;）

所以在你的控制器中你应该做

if (isset($_FILES['ImageTemp'])) { 
   // do something..
}

Yii框架CMultifileupload提交无法正常工作

1 个答案: