如何获取巨型属性的标记图像的网址值?
我应该按属性获取吗?
我如何在PHP中执行此操作?
$string = file_get_contents("http://ws.audioscrobbler.com/2.0/?method=artist.getTopAlbums&artist=enya&lang=pt&autocorrect=1&api_key=1d07ae6d0a77914229c0ccaa75867fdf");
$xml = new SimpleXMLElement($string);
$cover = $xml->topalbums->album->image["size"]['extralarge'];
var_dump($cover);
由于