Question

在我的场景中，hashTable就像这样

AId=1
BId=1
catalogId=10053
reason_1=RET-KP
reason_2=RET-KP
quantity_1=1.0
ItemId_1=468504
quantity_2=1.0
ItemId_2=468505

现在我需要在_i时删除所有reason_i=RET-KP件事即。 delete ItemId_1 & quantity_1 reason_i为reason_1，reason_2

的位置

那么我如何迭代这个hashTable并根据它们的值删除键（动态）并再次将它存储在hashTable中。

Answer 1

检查这将解决您的问题。

 package com.loknath.lab;



 public class HashTableDemo {
public static void main(String args[]) {

    Hashtable htable = new Hashtable(3);
    boolean deleteStatus;
    ArrayList<String> list = new ArrayList<String>();
    // populate the table
    htable.put("AId", 1);
    htable.put(" catalogId", 2);
    htable.put(" ItemId_1", 43);
    htable.put("ItemId_2", 43);
    htable.put("bid", 54.45);

    Set<String> keys = htable.keySet();

    for (String key : keys) {

        System.out.println(key);
        deleteStatus = check(key);
        if (deleteStatus) {
            list.add(key);
        }
    }

    for (String string : list) {
        htable.remove(string);
    }

}

public static boolean check(String key) {
    boolean status = false;
    status = key.contains("_");
    return status;
}

 }

如何从哈希表中删除这些值？

1 个答案: