Question

我需要创造 POST请求网址为http://url.com/api/auth/ 使用HTTP-Body authparams = {“login”：“login”，“password”：“pasword”} 我怎么能创造它？我试试

 HttpClient httpClient = new DefaultHttpClient();
        // Creating HTTP Post
        HttpPost httpPost = new HttpPost("http://url.com/api/auth/");
        // Building post parameters, key and value pair
        List<NameValuePair> nameValuePair = new ArrayList<NameValuePair>(2);
        nameValuePair.add(new BasicNameValuePair("login", "A@asd.ru"));
        nameValuePair.add(new BasicNameValuePair("password", "123"));
        // Url Encoding the POST parameters
        try {
            httpPost.setEntity(new UrlEncodedFormEntity(nameValuePair));
        } catch (UnsupportedEncodingException e) {
            // writing error to Log
            e.printStackTrace();
        }
        // Making HTTP Request
        try {
            HttpResponse response = httpClient.execute(httpPost);
            // writing response to log
            Log.d("myLogs:", response.toString());
            HttpEntity entity = response.getEntity();
            Log.d("myLogs:",EntityUtils.toString(entity) );
        } catch (ClientProtocolException e) {
            // writing exception to log
            e.printStackTrace();
        } catch (IOException e) {
            // writing exception to log
            e.printStackTrace();

        }

但是我得到了一个糟糕的结果

Answer 1

您需要将帖子数据转换为Json格式（您可以使用google library gson或使用org.json）。

然后将您的json字符串添加到帖子数据中 nameValuePair.add(new BasicNameValuePair("login", "A@asd.ru"))

Answer 2

我认为您错过了您发布的代码段。这只是向服务器发送 POST请求，但目前还没有处理来自它的响应。为此，您可以使用以下代码：

InputStream ips;
ips = response.getEntity().getContent();
final BufferedReader buf = new BufferedReader(new InputStreamReader(ips, "UTF-8"));

StringBuilder sb = new StringBuilder();
String s;
while (true) {
  s = buf.readLine();
  if ((s == null) || (s.length() == 0))
    break;
  sb.append(s);
}

buf.close();
ips.close();
Log.i("Response", "My response is: " + sb.toString());

Http请求与身体

2 个答案: