这是我从HTTP响应中收到的JSON字符串。
[{"ts":"1395318389","date":"2014-03-20","time":"12:26:21","nodeid":"1229001363","lat":"53.292425","lon":"-6.43203333333333","speed":"76","dir":"242","sv":"9","volt":"4187","rssi":"-69","us":"3","type":0,"net":"27202","height":"108","hdop":"9","cellid":"EB84","dd":6105,"ttf":"0","lac":"4E24","odo":"0","gle":"0"}]
我的课程设置如下
Friend Class SmartTrack_PostionList
Public positionList As SmartTrack_Postion()
End Class
Friend Class SmartTrack_Postion
Public ts As String
Public [date] As String
Public time As String
Public nodeid As String
Public lat As String
Public lon As String
Public speed As String
Public dir As String
Public sv As String
Public volt As String
Public rssi As String
Public us As String
Public type As String
Public net As String
Public height As String
Public hdop As String
Public cellid As String
Public dd As String
Public ttf As String
Public lac As String
Public odo As String
Public gle As String
End Class
我尝试了以下几行代码,但没有一行正常工作
Dim ser As New System.Web.Script.Serialization.JavaScriptSerializer
Dim getPositionList As SmartTrack_PostionList = DirectCast(ser.Deserialize(Of SmartTrack_PostionList)(getResult.ToString), SmartTrack_PostionList)
和
Dim ser As New System.Web.Script.Serialization.JavaScriptSerializer
Dim getPositionList As SmartTrack_Postion= DirectCast(ser.Deserialize(Of SmartTrack_Postion)(getResult.ToString), SmartTrack_Postion)
这确实有效,但我认为编码很糟糕。
Dim ser As New System.Web.Script.Serialization.JavaScriptSerializer
getResult = getResult.Replace("[", "")
getResult = getResult.Replace("]", "")
Dim dict As Dictionary(Of String, String) = ser.Deserialize(Of Dictionary(Of String, String))(getResult)
感谢您的任何帮助,谢谢。
吉姆
答案 0 :(得分:1)
您必须将JSON字符串反序列化为List(Of SmartTrack_Position)
,例如
Dim ser = New System.Web.Script.Serialization.JavaScriptSerializer
Dim json = getResult.ToString()
Dim getPositionList = ser.Deserialize(Of List(Of SmartTrack_Postion))(json)
答案 1 :(得分:0)
使用此课程
public class RootObject
{
public string ts { get; set; }
public string date { get; set; }
public string time { get; set; }
public string nodeid { get; set; }
public string lat { get; set; }
public string lon { get; set; }
public string speed { get; set; }
public string dir { get; set; }
public string sv { get; set; }
public string volt { get; set; }
public string rssi { get; set; }
public string us { get; set; }
public int type { get; set; }
public string net { get; set; }
public string height { get; set; }
public string hdop { get; set; }
public string cellid { get; set; }
public int dd { get; set; }
public string ttf { get; set; }
public string lac { get; set; }
public string odo { get; set; }
public string gle { get; set; }
}
然后像这样使用json.net
RootObject Json= JsonConvert.DeserializeObject<RootObject>(returnJson);