Question

我正在尝试在CMD提示符中运行命令以从我的SVN（TortoiseSVN 1.7.8）获取信息。在cmd提示符中，我输入：

cmd /c C:\Program Files\TortoiseSVN\bin\svn.exe info C:\MyCode\CurrProj\Ry1

我明白了：

'C：\ Program'未被识别为内部或外部命令，可操作程序或批处理文件。

这是有道理的，因为'C：\ Program'之后有一个空格。好的，如果我输入：

cmd /c "C:\Program Files\TortoiseSVN\bin\svn.exe" info C:\MyCode\CurrProj\Ry1

然后一切按预期工作。但是，如果位置（最后一个路径）包含空格：

cmd /c "C:\Program Files\TortoiseSVN\bin\svn.exe" info C:\MyCode\Curr Proj\Ry1

我明白了：

svn：E155007：'C：\ MyCode \ Curr'不是工作副本

所以这意味着SVN命令只运行并使用了部分代码位置。所以我也在这条道路上添加了引号：

cmd /c "C:\Program Files\TortoiseSVN\bin\svn.exe" info "C:\MyCode\Curr Proj\Ry1"

这让我回到了错误消息：

'C：\ Program'未被识别为内部或外部命令，可操作程序或批处理文件。

什么？？有人能解释为什么CMD提示没有正确解释这个问题吗？最后一个示例不应该使用“关闭”选项启动CMD提示并运行：

"C:\Program Files\TortoiseSVN\bin\svn.exe" info "C:\MyCode\Curr Proj\Ry1"

如果我跑： "C:\Program Files\TortoiseSVN\bin\svn.exe" info "C:\MyCode\Curr Proj\Ry1" 它本身就可以正常工作，但是这个命令将在一些C＃代码中以编程方式创建的进程中运行：

System.Diagnostics.ProcessStartInfo procStartInfo =
                new System.Diagnostics.ProcessStartInfo("cmd", "/c " + command);

其中command = "C:\Program Files\TortoiseSVN\bin\svn.exe" info "C:\MyCode\Curr Proj\Ry1"

Answer 1

摘录自cmd /help：

If /C or /K is specified, then the remainder of the command line after
the switch is processed as a command line, where the following logic is
used to process quote (") characters:

    1.  If all of the following conditions are met, then quote characters
        on the command line are preserved:

        - no /S switch
        - exactly two quote characters
        - no special characters between the two quote characters,
          where special is one of: &<>()@^|
        - there are one or more whitespace characters between the
          two quote characters
        - the string between the two quote characters is the name
          of an executable file.

    2.  Otherwise, old behavior is to see if the first character is
        a quote character and if so, strip the leading character and
        remove the last quote character on the command line, preserving
        any text after the last quote character.

Answer 2

不要将你的参数与文件名

联系起来

using (Process p = new Process())
{
   p.StartInfo.FileName = "cmd.exe";
   p.StartInfo.Arguments = "/c \"c:\\Program Files\\..blah\"";
   p.Start();
}

您还需要使用转义字符

在路径周围添加引号

\" gives you "

如何正确地将完整文件名传递给`cmd / c`？

2 个答案: