PHP OOP错误 - 缺少User :: __ construct（）的参数1

Question

我一直在谷歌上搜索这个错误，但我无法解决。

我在user.php文件中有我的用户类：

<?php

/*
 * To change this license header, choose License Headers in Project Properties.
 * To change this template file, choose Tools | Templates
 * and open the template in the editor.
 */

class User 
{

   private $usr_id;
   private $utp_id;
   private $usr_login;
   private $usr_password;
   private $usr_firstname;
   private $usr_lastname;
   private $usr_active;
   private $usr_created_usrid;
   private $usr_created_date;
   private $usr_modified_userid;
   private $usr_modified_date;

   function __construct($usr_id, $utp_id, $usr_login, $usr_password, $usr_firstname, $usr_lastname, 
           $usr_active, $usr_created_usrid, $usr_created_date, $usr_modified_userid, $usr_modified_date) 
   {
       $this->usr_id = $usr_id;
       $this->utp_id = $utp_id;
       $this->usr_login = $usr_login;
       $this->usr_password = $usr_password;
       $this->usr_firstname = $usr_firstname;
       $this->usr_lastname = $usr_lastname;
       $this->usr_active = $usr_active;
       $this->usr_created_usrid = $usr_created_usrid;
       $this->usr_created_date = $usr_created_date;
       $this->usr_modified_userid = $usr_modified_userid;
       $this->usr_modified_date = $usr_modified_date;
   }

  // some code to generate getters and setters

?>

我还有另一个使用pdo登录的文件，userDAO.php：

<?php

/*
 * To change this license header, choose License Headers in Project Properties.
 * To change this template file, choose Tools | Templates
 * and open the template in the editor.
 */

require_once '../db/accessDB.php';
require_once '../class/user.php';

class UserDAO 
{


    public function loginUser($usr_login, $usr_password)
    {
        try {
            $pdo = AccessDB::getConnectionPDO();

            $pwd_md5 = md5($usr_password);

            $user = new User('', '', $usr_login, $pwd_md5);

            $sql = 'SELECT '
                    . ' a.utp_id, a.usr_firstname, a.usr_lastname,'
                    . ' b.utp_type'
                . ' FROM lm_user a, lm_usertype b'
                . ' WHERE'
                    . ' a.utp_id=b.utp_id AND'
                    . ' a.usr_login="?" AND a.usr_password="?" AND  '
                    . ' a.usr_active="1"  ';

            $stmt = $pdo->prepare($sql);
            $stmt->bindParam(1, $user->getUsr_login(), PDO::PARAM_STR);
            $stmt->bindParam(2, $user->getUsr_password(), PDO::PARAM_STR);

            echo $sql;

        } catch (Exception $ex) {
            throw $ex;
        }
    }


}

?>

问题是，当我想测试它时，我有以下错误：

可能是什么问题？问候。

Answer 1

$user = new User('', '', $usr_login, $pwd_md5);，它与User类构造函数参数__construct($usr_id, $utp_id, $usr_login, $usr_password, $usr_firstname, $usr_lastname, $usr_active, $usr_created_usrid, $usr_created_date, $usr_modified_userid, $usr_modified_date)不匹配。由于所有参数都不是选项，因此您需要在创建对象时强制传递所有参数。