我有以下查询返回一个Cursor,该查询基于有多少记录的offreasontypeid为' 2'。它工作正常。
如何运行相同的查询,但返回所有记录的光标,其中offreasontypeid为' 2'或者' 0'?
// table AwayReason column names
public static final String C_AWAYREASON_ID_INDEX = BaseColumns._ID;
public static final String C_AWAYREASON_ID = "awayreasonid";
public static final String C_AWAYREASON_NAME = "awayreasonname";
public static final String C_AWAYREASON_TYPE_ID = "awayreasontypeid";
public Cursor queryCarerAwayReasons(){
SQLiteDatabase db = dbhelper.getReadableDatabase();
String[] carer = { "2" };
Cursor c = db.rawQuery("SELECT * FROM " + DBHelper.TABLEAWAYREASON + " WHERE awayreasontypeid = ?", carer);
return c;
}
提前致谢
马特
答案 0 :(得分:1)
您可以使用IN
:
String[] carer = { "2", "0" };
Cursor c = db.rawQuery("SELECT * FROM " + DBHelper.TABLEAWAYREASON + " WHERE awayreasontypeid IN (?,?)", carer);